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Sever21 [200]
3 years ago
11

Two school buses leave the same school at the same time, but are headed in opposite directions. One bus traveled 45 miles per ho

ur and the other bus traveled 40 miles per hour. How long until the buses are 170 miles apart?
Mathematics
2 answers:
sveta [45]3 years ago
5 0

Answer:

2 hours

Step-by-step explanation:

For if you start at 1 hour you end up with one bus 45 miles away from the school and the other 40 miles. If you then add these then you find out how far apart they are which is 85 at this point and time. If you do another hour the bus going 45 is now 90 miles away from the school. The other one will be 80. After you add these two number to find how far apart they are you end up with 170.

Bingel [31]3 years ago
4 0

45 mph: 3 hours 46 minutes 40 seconds

40 mph: 4 hours 15 minutes

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(x⁴)(x³)

x⁷

(12x⁵)/(36x)

x⁴/3

(x⁴y³)/(x⁴y)

y²

(-2x³)(-4x²)

8x⁵

(-3x²)³

-27x⁶

(x³y⁵)/(xy²)

x²y³

2x³(10x)³

2000x⁶

(x⁷y²)/(x⁴y²)

x³

x⁻⁴

1/x⁴

(-21x⁵y²)/(7x⁴y⁵)

-(3x)/y³

3x⁻³

3/x³

(32x³y²z⁵)/(-8xyz²)

-4x²yz³

...

x⁴y⁴

(4x⁷/7y²)²

(16x¹⁴)/(49y⁴)

...

8x³

4⁻⁴

1/(4⁴) or 1/256

...

a⁵

8⁻²

1/(8²) or 1/64

...

2c⁷

x⁻²

1/x²

...

9x²

x⁻³

1/x³

...

a⁴

x⁻⁴

1/x⁴

...

4c⁵

x²y⁻³

(x²)/(y³)

When multiplying monomials with the same base, ___________ the exponents

add

x³y⁻²

(x³)/(y²)

When dividing monomials with the same base, ______________ the exponents

subtract

x²y³z⁻⁴

(x²y³)/(z⁴)

When raising a power to a power, ________________ the exponents

multiply

x²y⁻³z⁴

(x²z⁴)/(y³)

x⁻²y⁻³

1/(x²y³)

A base raised to a zero exponent equals________________

one

(2m²)(2m³)

4m⁵

(x/y)⁻¹

y/x

4r⁻³(2r²)

8÷r

(x²/y²)⁻¹

y²/x²

2x³y⁻³(2x⁻¹y³)

4x²

(x³/y³)⁻¹

y³/x³

2y²(3x)

6y²x

(x/y)⁻²

y²/x²

4a³b²(3a⁻⁴b⁻³)

12÷(ab)

(x²/y²)⁻³

y⁶/x⁶

4r⁰

4

(2/3)⁻²

9/4

(4xy)⁻¹

1÷(4xy)

(4/5)⁻²

25/16

(3/4)⁻²

16/9

(3/4)⁻¹

4/3

(x³/x⁻⁶)

x⁹

(x²/x⁻⁵)

x⁷

x⁰

1

y⁰

1

x²y⁰

x²

x²y³z⁰

x²y³

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1

100⁰

1

(-99)⁰

1

x⁰(x⁴)(x⁻⁶)

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(x⁻³)/(x⁴)

1/x⁷

(x⁻⁴)/(x⁵)

1/x⁹

(4x³/2x⁵)⁰

1

(x⁻⁵y⁴)/(z⁻²)

(y⁴z²)/x⁵

(15x⁶y⁻⁹)/(5xy⁻¹¹)

3x⁵y²

(48x⁶y⁷z⁵)/(-6xy⁵z⁶)

-(8x⁵y²)/z

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Simplify (y²z²)(y³z)

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Simplify (a²b⁴)(a²b⁴)

a⁴b⁸

Simplify (ab²)(a³b²)

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Simplify (2x²)(3x⁵)

6x⁷

Simplify (5x⁷)(4x²)

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Simplify (4xy³)(3x³y⁵)

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Simplify (7x⁵y²)(x²y³)

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Simplify (-5x³)(3x⁸)

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Simplify (-6x)²

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(3xy²)²

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(2x³y⁴)²

4x⁶y⁸

Find the area of a rectangle if the length is x² and the width is x⁵.

x⁷

Find the area of a square if the side length is xy.

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Simplify (2ab²c²)(4a³b²c²)

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(-4x²y)²(-½xy²)

-8x⁵y⁴

(0.2x²y³)²

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(0.4x³)³

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