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3 years ago

What is the correct multiplication of a cross product to solve for the missing dimension?

Mathematics

2 answers:

Olegator [25]3 years ago

7 0

Answer:

Step-by-step explanation:

The two rectangles are similar. The shapes are the same but the sizes are different. The ratio of the smaller rectangle to the bigger one is constant.

Comparing the sides of the two rectangles, we would take ratio of the width of both rectangles and equate it to ratio of the lengths of both rectangles. It becomes

3/5 : 12 = x : 20

(3/5)/12 = x/20

3/5 × 1/12 = x/20

3/60 = x/20

Cross multiplying

60 × x = 20 × 3

60x = 60

x = 60/60 = 1

The enlargement is in a scale of 5. Multiplying any length on the smaller rectangle by 5 will give the corresponding length of the bigger

Murljashka [212]3 years ago

7 0

Answer:

(3/5)(20)=12(x)

Step-by-step explanation:

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3 years ago

Is 5000 cm greater or less than 5 m

Alenkasestr [34]

Answer: 5000 cm is greater than 5 m

Step-by-step explanation:

When you convert 5000 cm to m 5000 cm is equal to 50 m so 5000 cm is greater than 5 m

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3 years ago

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Calculate the slope of a line that goes through the points: (5, 7) & (2, 7). Leave your solution as a simplified (improper)

Fiesta28 [93]

Answer:

Step-by-step explanation:

m=(y2-y1)/x2-x1), if m is slope and the 2 points are (x1, y1), (x2, y2).

m=(7-7)/(2-5)

m=0/-3

m=0

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3 years ago

A rectangular plot of land is to be enclosed by a fence. One side is along a river, and does not need to be enclosed. If the tot

Bad White [126]

Answer:

Width 150 meters.

Length = 350 meters.

Step-by-step explanation:

Let us assume the width of the fence = k meters

So, both sides = k + k = 2k meters

Also, the TOTAL fencing length = 600 m

So, the one side length of the fence = (600 - 2 k) meters

AREA = LENGTH x WIDTH

⇒ A(k) = (600 - 2k) (k)

or, A = -2k² + 600 k

The above equation is of the form: ax² +bx + C

Here: a = - 2 , b = 600 and C = 0

As a< 0, the parabola opens DOWNWARDS.

Here, x value is given as: $x = \frac{-b}{2a}$

Solving for the value of k similarly, we get:

$k = \frac{-b}{2a} = \frac{600}{2(-2)} = 150$

Thus the desired width = k = 150 meters

So, the desired dimensions of the plot is width 150 meters.

And length = 650 - 2k = 650 - 300 = 350 meters.

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3 years ago