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Phoenix [80]
3 years ago
13

An investment has an expected return of 11 percent per year with a standard deviation of 26 percent. Assuming that the returns o

n this investment are at least roughly normally distributed, how often do you expect to earn less than -15 percent?
Business
1 answer:
Keith_Richards [23]3 years ago
4 0

Answer:

P(X

And we can find this probability using the normal standard distribution table or excel and we got:

P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the expected return, and for this case we know the distribution for X is given by:

X \sim N(11,26)  

Where \mu=11 and \sigma=26

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard distribution table or excel and we got:

P(Z

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Answer:

D. specific performance.

Explanation:

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6 0
3 years ago
You can now sell 70 cars per month at $35,000 per car, and demand is increasing at a rate of 4 cars per month each month. What i
Eduardwww [97]

Answer:

the fastest we could drop your price before your monthly revenue starts to drop is $2,000

Explanation:

Data provided in the question:

Cars sold per month, Q =  70 cars

Price of each car, P = $35,000

Rate of increase in demand, \frac{dQ}{dt} = 4 cars per month

Now,

Revenue, R = Price(P) × Quantity (Q)

Thus,

When monthly revenue starts to drop i.e \frac{dR}{dt} < 0

⇒ \frac{dR}{dt} = \frac{d(PQ)}{dt} < 0

or

⇒ P\frac{dP}{dt}+Q\frac{dQ}{dt} < 0

or

⇒ 70\times\frac{dP}{dt}+35,000\times4 < 0

or

⇒ 70\times\frac{dP}{dt} < - 140,000

or

\frac{dP}{dt} < - 2,000

Hence,

the fastest we could drop your price before your monthly revenue starts to drop is $2,000

7 0
3 years ago
On August 1, Kim Company accepted a 90-day note receivable as payment for services provided to Hsu Company. The terms of the not
Andreyy89

Answer:

credit to interest revenue for $132

Explanation:

given data

face value = $8,800

interest rate = 6 %

time = 90 days

solution

if we see here journal entry that is

date                  particular                                   debit                      credit

October 30       cash A/C                                   $8932

                          to notes payable                                                    $8800

                          to interest revenue                                                $132

                          ( $8800× 6% × \frac{90}{360} )

so here credit to interest revenue for $132

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C is your answer C) master budget
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