All categories

2 years ago

7w+6-3w Please help I don’t understand how to do this

Mathematics

1 answer:

Oksana_A [137]2 years ago

6 0

Answer:

4w + 6

Step-by-step explanation:

Group like terms

7w - 3w + 6 = 4w + 6

Hope this Helps :)

You might be interested in

The cartesian equation, y = 4, is equivalent to the polar equation, _____.

jolli1 [7]

This is how you would solve the question.

4 0

3 years ago

One side of a rectangle is parallel to the x-axis. One vertex of the rectangle is located at (5,2) and another vertex at (1,4).

harina [27]

Answer:

(1,2) and (5,4)

Step-by-step explanation:

Hello There!

I had made a graph to make it easier to understand.

The points given to us are represented by the green points

The points that would make a rectangle with lines that are parallel with the x axis would be (1,2) and (5,4) (represented by the red points)

As you can see the points added had created a rectangle with sides that are parallel with the x axis

This meets all of the requirements therefore the other two vertices would have the points (1,2) and (5,4)

8 0

2 years ago

Simplify the expression 8h + (-7.7d) -17 +5d -3.2h =

Anit [1.1K]

Answer:

(8h - 3.2h) + (-7.7d + 5d) - 17 = 4.8h - 2.7d - 17

4 0

2 years ago

Read 2 more answers

Find the missing number.

Vinil7 [7]

Answer: 20%

Step-by-step explanation:

If we let the original amount be x, then after increasing it by 25%, we now have 1.25x

To get this back to x, we need to do 1.25x*(something) = x

this gives us that something = 1/1.25 = 0.8

meaning you need to decrease it by 100% - 80% = 20%

4 0

2 years ago

Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start

Kamila [148]

Option B: $\frac{1}{(m-4)(m-3)}$ is the correct answer.

Explanation:

The given expression is $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$

Simplifying the expression, we have,

$\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}$

Factor the equations, $m^{2}-16\right$ and $m^{2}-9$ ,we get,

$m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)$

$m^{2}-9=m^{2}-3^2=(m+3)(m-3)$

Substituting these factored expressions in the above expression, we have,

$\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}$

Cancelling the common terms $m+3$ and $m+4$ , we get,

$\frac{1}{(m-4)(m-3)}$

Thus, the expression equivalent to $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$ is $\frac{1}{(m-4)(m-3)}$

Hence, Option B is the correct answer.

3 0

3 years ago

Read 2 more answers