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Alex787 [66]
3 years ago
14

Jayla buys and sells vintage clothing. She bought two blouses for $25.00 each and later sold them for $38.00 each. She bought th

ree skirts for $15.00 each and later sold them for $26.00 each. She bought five pairs of pants for $30.00 each and later sold them for $65.00 each
Mathematics
1 answer:
lianna [129]3 years ago
7 0

Answer:

She's now $234.00 richer!

Hope this helps!

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0.16+0.45 eaqkesbnnn
jarptica [38.1K]
Sorry, but I have no idea what your "<span>eaqkesbnnn" means.
</span>
If you were supposed to add 0.16 and 0.45, the correct answer would be 0.61.
4 0
2 years ago
Read 2 more answers
Determine if the points A(1,-3), B(4,4), and C(5,8) are collinear.
myrzilka [38]

Answer:

no

Step-by-step explanation:

since;

(4--3)/(4-1)≠(8-4)/(5-4)

4 0
2 years ago
A 200 pound person weighs 33 pounds on the moon.​ Type the answers in the boxes below. 1. How much did the person's weight decre
Kitty [74]
If you’re asking for just the number of pounds then the answer is
200-33= 167 pounds

If you’re asking for a percentage of decrease it will be

200 - 33 = 177
_______ ____ = 0.885 x 100 will equal to 88.5% decrease.
200 200
8 0
1 year ago
If Aliya can make 10 bracelets in 2 days, how long will it take her to make 35 bracelets?​
kirill [66]

Answer:

about 6 1/2

Step-by-step explanation:

10x3=30

10÷2=5

6 0
2 years ago
A tank contains 1,000 L of brine with 12 kg of dissolved salt. Pure water enters the tank at a rate of 10 L/min. The solution is
vivado [14]

Answer:

y = 12*e^[-t/100]

Step-by-step explanation:

We have to mix problems we use:

dy / dt = (rate in) - (rate out)

The water entering the tank at a speed of 10 L / min but it has no salt, therefore

rate in = 0

The tank has 1000 liters of brine with 12 kg of salt initially, therefore the concentration of salt at time "t" is:

y (t) / 1000

then rate out would be:

rate out = y (t) / 1000 * 10 = y (t) / 100

The difference equation would then be:

dy / dt = 0 - y (t) / 100

1 / y (t) * dy = 1/100 * dt

We integrate from both sides and we have:

ln y = - (1/100) * t + C1

y = e ^ [- (1/100) * t + C1]

y = e ^ [- (1/100) * t] * e ^ [C1]

We assume that C = e ^ [C1]

Thus:

y = C * e ^ [- (1/100) * t]

now y = 12 to t = 0, replacing:

12 = C * e ^ [- (1/100) * 0]

12 = C, therefore we would have:

y = 12 * e ^ [- t / 100]

5 0
3 years ago
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