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Anna35 [415]
3 years ago
15

One litre of milk is poured into a cylindrical container of radius 10 cm. Calculate the depth of the milk in cm)to 2 dp. ( take

pi = 3.142)​
Mathematics
1 answer:
wel3 years ago
8 0

Answer:

Depth=3.18cm

Step-by-step explanation:

V=πr2h

1LITRE=1000CM3

v=1000cm³

1000cm3=3.142×10²×Depth

Depth= 1000/3.142×100

Depth=3.18cm

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Find mMK................
Gnesinka [82]

Answer:

Approximately mMK is 53 degrees

Step-by-step explanation:

Here, we want to find the length of MK

As we can see, we have a right triangle at LNK

so

let us find the angle at L first

9 is adjacent to the angle at L and also, 15 is the hypotenuse of the angle at L

so the trigonometric identity that connects adjacent to the hypotenuse is the cosine

It is the ratio of the adjacent to the hypotenuse

So;

cos L = 9/15

L = arc cos (9/15)

L = 53.13 degree

Approximately, L = 53 degrees

so now, we want to get the arc length MK

We are to use the angle-arc relationship here

Using this; arc length MK is equal to the measure of L at the center which is 53 degrees

3 0
3 years ago
What are the zeros of this function?
Marina86 [1]
Where is the function?
7 0
3 years ago
Ahhhh i need help again.
qwelly [4]

Answer:

B

Step-by-step explanation:

A. these simply to 21 + 7x and 21 + 3x

  • this one is incorrect because the 7x and 3x are different

B. these simplify to 10 + x and 10 + x

  • this is the correct one since they are exactly the same

C. these simplify to 21x and 7x + 21

  • these two are not the same because one expression has only a number with a variable but the other one has a number with a variable <em>and </em>another number

D. these simplify to  \frac{7}{3-x}  and  \frac{7}{x-3}

  • in subtraction, the order of the 3 and the x matters, so the equations are not the same
  • example: 6 - 4 = 2 but 4 - 6 = -2
3 0
3 years ago
To find out approximately how many minutes students in a high school are spending texting while in class, the guidance counselor
slega [8]

Add all the minutes together, then divide by the number of students:

21+35+77+48+24+29+37+98+30+7 = 406 total minutes

10 students.

Average = 406 / 10 = 40.6 minutes per week.

The answer is A.

6 0
3 years ago
A ladder is leaning against a wall. The top of the ladder is 9 feet (ft) above the ground. If the bottom of the ladder is moved
Komok [63]

Step 1

<u>First situation</u>

when a ladder is leaning against a wall

Let

x-------> the distance of the bottom of the ladder from the wall

L-------> the length of the ladder

<u>Find the length of the ladder</u>

Applying the Pythagorean Theorem

L^{2} =x^{2}+ 9^{2} ------> equation 1

Step 2

<u>Second situation</u>

when the ladder will be lying flat on the ground

<u>Find the length of the ladder</u>

In this situation the length of the ladder is equal to

L=x+3

square both sides

L^{2}=(x+3)^{2} ------> equation 2

Step 3

equate equation 1 and equation 2

x^{2}+ 9^{2}=(x+3)^{2}\\x^{2}+81=x^{2} +6x+9\\ 6x=81-9\\6x=72\\x=12\ ft

therefore

<u>the answer is</u>

the length of the ladder is 12\ ft

see the attached figure to better understand the problem

5 0
3 years ago
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