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3 years ago

I NEED THIS PLEASE these are all my points!

Mathematics

2 answers:

sertanlavr [38]3 years ago

7 0

Answer:

m>14 or m< -2

Step-by-step explanation:

mylen [45]3 years ago

6 0

The answer is: M>14 or m ≤-2

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In right angled triangle (not drawn to scale) measurment (in cm) of two sides are indicated in figure Find value of x in case. (

lisabon 2012 [21]

Answer:

5.29 units

Step-by-step explanation:

By Pythagoras theorem:

${6}^{2} + {x}^{2} = {8}^{2} \\ 36 + {x}^{2} = 64 \\ {x}^{2} = 64 - 36 \\ {x}^{2} = 28 \\ x = \sqrt{28} \\ x = 5.29150262 \: units \\ x \approx 5.29 \: units$

4 0

3 years ago

A certain high school class consists of juniors and seniors. There are

Genrish500 [490]

Answer:

10 SENIORS

Step-by-step explanation:

x=# of seniors

y=# of juniors

x+y=23, x=2y-7

plug the value of x in the second equation into the first
(2y-7)+y=23
Remove parentheses
2y-7+y=23
Combine like terms
3y-7=23
Add 7 to BOTH sides
3y=30
divide BOTH sides by 3
3y/3=30/3
y=10
There are 10 juniors in the class

FINAL STEPS
Plug y (which is 10) into the first equation
x+y=23
x+10=23
subtract 10 from BOTH sides
x=13
Since X equals the number of seniors, there are 10 seniors in the class

8 0

3 years ago

Find quotient ..........

Tanya [424]

The answer is C. 68/5 - 54/5i

8 0

3 years ago

Brad drives 527 miles on 17 gallons. How many miles does Brad drive on one gallon? (5 points + Brainiest!)

Ostrovityanka [42]

Answer:

Step-by-step explanation:

527 / 17 = 31

6 0

3 years ago

Suppose that we wanted to estimate the true average number of eggs a queen bee lays with 95 percent confidence. The margin of er

svetoff [14.1K]

Answer:

At least 1537 samples needed to estimate the true average number of eggs a queen bee lays with 95 percent confidence

Step-by-step explanation:

Minimum sample size required can be found using the formula

N≥ $(\frac{z*s}{ME} )^2$ where

N is the sample size

z is the corresponding z-score of 95% confidence level (1.96)

s is the standard deviation (10)

ME is the margin of error (0.5)

then N≥ $(\frac{1.96*10}{0.5} )^2$ =1536.64

Then, at least 1537 samples needed to estimate the true average number of eggs a queen bee lays with 95 percent confidence

6 0

3 years ago