Power(p) = 2kW
Time(t)= 3 h
Work done(w) = ?
p = w / t
w = p × t
w = 2kW × 3 h
w = 6kWh
Converting 6kWh to Joules,
6kWh
6×(10^3)h ( k = 10^3 )
6×10^3×(60×60) ( 1 hour = 60 × 60 sec)
2.2×10^7 J in 2 significant figures
Answer:
B.
I think.
Explanation:
Mars doesn't have that much of an atmosphere!
Have a great day!
Poder = (resistencia) x (corrente)²
Poder = (10 ohms) x (5 A)²
<em>Poder = 250 watts </em>(250 Joule por segundo)
2 horas = 7,200 segundos
Energia = (250 joule/seg) x (7,200 seg)
<em>Energia = 1,800,000 Joules</em>
The appropriate response is Zero degrees. The beam will leave the two mirrors along a way parallel to the one it came in on. This is the guideline of the corner reflector, which is frequently utilized as a radar target. Take note of that the corner reflector utilizes three reflecting surfaces (that are set up at 90o from each other) rather than the two like are being utilized here. Wikipedia has a truly awesome drawing that shows this two-dimentional issue pleasantly. A moment connection is given to the article on the corner reflector and the 3-D angles.
