Answer:
first number(x) = 2 second number(y)= 6
Step-by-step explanation:
This is an example of a simultaneous equation.
First write this word problem as equations, where x is the "first number" that you've mentioned and y is the "second number".
x + 2y = 14 (equation 1)
2x + y = 10 (equation 2)
This is solved using the elimination method.
We need to make one of the coefficients the same - in this case we can make y the same. In order to do this we need to multiply equation 2 by 2, so that y becomes 2y.
2x + y = 10 MULTIPLY BY 2
4x + 2y = 20 (this is now our new equation 2 with the same y coefficient)
Now subtract equation 1 from equation 2.
4x - x + 2y - 2y = 20 - 14 (2y cancels out here)
3x = 6
x = 2
Now we substitute our x value into equation 1 to find the value of y.
2 + 2y = 14
2y = 12
y = 6
Hope this has answered your question.
Answer:

Step-by-step explanation:
First find difference between the divisors and remainders.

Here, the difference between the divisors and remainders is equal.
So, the required number is equal to LCM of 

LCM of 
Required Number 
Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4
Therefore, the system has infinite number of solutions.
Answer:
2
Step-by-step explanation:
Answer:
9 1/3
Step-by-step explanation:
That is wrong i tried to answer it but messed up so don't use it