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Sidana [21]
3 years ago
6

Point M is the midpoint of AB if the coordinates of A are (-3,6) and the coordinates of M are (-5,2) what are the coordinates of

B ?
Please answer #5

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

The coordinates of point B are (-7 , -2)

Step-by-step explanation:

* Lets explain how to solve the problem

- The mid-point (x , y) of the line whose endpoints are (x1 , y1) and

 (x2 , y2) is x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

∵ M is the midpoint of AB

∵ The coordinates of point A are (-3 , 6)

∵ The coordinates of point M are (-5 , 2)

- Let the coordinates of point A are (x1 , y1) , The coordinates of

 point B are (x2 , y2) and The coordinates of point M are (x , y)

∴ x = -5 , x1 = -3 and y = 2 , y1 = 6

- Lets use the rule of the mid point to find x2 , y2

∵ -5=\frac{-3+x_{2}}{2} ⇒ multiply both sides by 2

∴ -10=-3+x_{2} ⇒ add 3 to both sides

∴ -7 = x2

∵ 2=\frac{6+y_{2}}{2} ⇒ multiply both sides by 2

∴ 4=6+y_{2} ⇒ subtract 6 from both sides

∴ -2 = y2

∵ The coordinates of point B are (x2 , y2)

∴ The coordinates of point B are (-7 , -2)

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Arlecino [84]

Answer:

$66.24

Step-by-step explanation:

TIP:

55.20 x 0.15 = 8.28

TAX:

55.20 x 0.05 = 2.76

Answer:

55.20 + 8.28 + 2.76 = 66.24

(Also always tip your server 20% unless they were bad)

7 0
3 years ago
Combine like terms: 3p2q2-3p2q3+4p2q3-3p2q2+pq PLEASE HELP!!! ASAP!!!
ch4aika [34]

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

7 0
3 years ago
Seattle, WA and San Francisco, CA lie on the same longitudinal line. San Francisco is at 38° latitude and Seattle is at 47° lati
Helen [10]

Step 1.

Calculate measure of angle α:

47^o-38^o=9^o

Step 2.

Calculate what fraction of the angle 360° ​​is the angle α:

\dfrac{9^o}{360^o}=\dfrac{1}{40}

Step 3.

Calculate the circumference of the Earth (circle):

C=2\pi r\to C=2\pi\cdot4000=8000\pi\ mi

Step 4.

The length of arc is equal 1/40 of the circumference:

\dfrac{1}{40}C=\dfrac{1}{40}\cdot8000\pi=200\pi\ mi

\pi\approx3.14\to\dfrac{1}{40}C\approx200\cdot3.14=628\ mi


<h3>Answer: A) 628 miles</h3>

7 0
4 years ago
What are the factors of 5x2 + 39x − 8?
prisoha [69]

Answer:

C. (5x - 1)(x + 8)

Step-by-step explanation:

In a factoring problem by hand, the common steps to solve would be the "AM" method, or (Add-Multiply). Simply stated, finding what adds to the x-coeficient and what multiplies to the constant. In this case, what adds to 39(x) and what multiplies to 8. Just reading that, we can see that there aren't any numbers that can do that, so we have to improvise. Set up the problem equal to something that it can factor into:

  1. <em>Multiply the 5 and -8</em> = -40: <em>this is what we will factor</em>
  2. <em>The factors with add to 39 are 40 and -1</em>.
  3. <em>Set up the problem:</em>

5x^{2}+39x-8 = 5x^{2}+40x-x-8

Now, we can fo the math:

5x^{2} -8 = 5x^{2} -8

8(5x - 1) + x(5x - 1)

<em>Factor (5x - 1) from this:</em>

(5x - 1)(x + 8)

And we have our answer.

4 0
3 years ago
(11c^4)^3 ? I need help
Bad White [126]
To do this, you cube each section. You cube the 11 and the c^4. 11^3=1331 and (c^4)^3=c^12 (You multiply the 2 exponents). So your answer is 1331c^12
5 0
3 years ago
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