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Lubov Fominskaja [6]
3 years ago
10

How many thirds are there in 10

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
6 0

Answer: 30 thirds because if you divide 10 by 1/3 you get 30.


Inessa [10]3 years ago
3 0

Answer:

There are three and 1/3

Step-by-step explanation:

it is simple plainly obvious

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Complete the table for the given rule.<br> Rule: y = 6x-4<br> Please help
d1i1m1o1n [39]

y = 6x - 4

Substitute the given x values to solve for y.

x = 1:

y = 6(1) - 4

y = 6 - 4

y = 2

1 = 2

x = 3:

y = 6(3) - 4

y = 18 - 4

y = 14

3 = 14

x = 10:

y = 6(10) - 4

y = 60 - 4

y = 56

10 = 56

x                y

1                 2

3               14

10             56

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3 years ago
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We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
3 years ago
Claire get a breakfast to go at a local store. She eats 2 pieces of buttered toast and a glass of juice for breakfast every day.
Luda [366]

Answer:

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Step-by-step explanation:

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3 0
4 years ago
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Kay [80]

Answer:

f(x) = -2x+5

f(x+h) = -2x -2h +5

g(x) = -4x-2

g(x+h) = -4x -4h -2

h(x) = 4x^2+1

h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1

Q(x) = -3x^2 +4

Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4

3 0
2 years ago
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