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4 years ago

5

If M is the midpoint of segment AB, then which of the following statements is/are true? AB=MB AM=MB Segment AM is congruent to s

egment MB.

1 answer:

Archy [21]4 years ago

3 0

AB is the large segment.

AM is half of the large segment.

MB is the second half of the large segment.

AM = MB is true.

Segment AM is congruent to segment MB is true.

AB = MB is false.

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Birds burgers barn sold 485 hamburgers today. The number sold with cheese wise half the number sold without cheese. How many of

frez [133]

Answer:

The number of hamburgers sold with cheese was 165 and the number of hamburgers sold without cheese was 330

Step-by-step explanation:

<u><em>The correct question is</em></u>

Birds burgers barn sold <em>495 hamburgers</em> today. The number sold with cheese wise half the number sold without cheese. How many of each kind were sold?

Let

x -----> the number of hamburgers sold with cheese

y -----> the number of hamburgers sold without cheese

we know that

$x+y=495$ -----> equation A

$x=\frac{1}{2}y$ ----> equation B

substitute the equation B in equation A and solve for y

$y+\frac{1}{2}y=495$

$\frac{3}{2}y=495$

$y=495(2)/3$

$y=330$

Find the value of x

$x=\frac{1}{2}330=165$

therefore

The number of hamburgers sold with cheese was 165 and the number of hamburgers sold without cheese was 330

4 0

3 years ago

5/x+3 take away 1/x-2 equals to 1. solve two possible answers for x

satela [25.4K]

Answer:

<h3><u>Solution</u><u>:</u><u>-</u></h3>

First write the given equation

$\qquad{:}\longrightarrow$ $\sf \dfrac {5}{x+3}-\dfrac{1}{x-2}=1$

$\qquad{:}\longrightarrow$ $\sf \dfrac {5 (x-2)-1 (x+3)}{(x+3)(x-2)}=1$

$\qquad{:}\longrightarrow$ $\sf \dfrac {5x-10-x }{x^2-6x-6} =1$

use cross multiplication method

$\qquad{:}\longrightarrow$ $\sf 5x-x-10=x^2-6x-6$

$\qquad{:}\longrightarrow$ $\sf x^2-6x-6=4x-10$

$\qquad{:}\longrightarrow$ $\sf x^2-6x-4x-6+10=0$

$\qquad{:}\longrightarrow$ $\sf x^2-10x+4=0$

use quadratic formula

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {-b\underline{+}\sqrt {b^2-4ac}}{2a}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10\underline{+}\sqrt {(-10)^2-4×1×4}}{2×1}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10\underline{+}\sqrt{100-16}}{2}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10\underline{+}\sqrt {84}}{2}$

$\qquad{:}\longrightarrow$ $\sf x=\dfrac {10+\sqrt {84}}{2}\quad or\quad x=\dfrac {10-\sqrt{84}}{2}$

8 0

3 years ago

Triple u then divide 3 by the result?

kkurt [141]

Answer:

$beinggreat78~is~here~to~help!$

The equation should look something like this.

$\frac{u(3)}{3}$

Be careful with your use between cubing and multiplying; Cubing is multiplying the number by itself multiple times, while multiplying is like repeated adding, yet much easier.

In this case, if it says triple, I highly recommend multiplying by 3, which is what I did, it only looks different because it is in parentheses.

What have we learned?

<h3>We learned how to write algebraic equations, and some further information on multiplying.</h3>

7 0

2 years ago

The yellow dog is smaller than the brown dog but larger than the white dog. The black dog is smaller than the white dog and the

mrs_skeptik [129]

the white dog

i think because it’s smaller than the yellow and all the others, i hope this is right i’m kinda dumb but yeah

7 0

4 years ago

Read 2 more answers

Simplify the expression by combining like terms<br>14g-6-13g-7

frozen [14]

Answer:

g-13

Step-by-step explanation:

subtract 14g from 13 making it g and add 6+7

Hope this helps :P

7 0

3 years ago

Read 2 more answers