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slamgirl [31]
3 years ago
8

Evaluate the following expression when x = 3 and y = 4:

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0
--------------------------

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A cockroach traveling 2 feet per second takes how long to scurry a distance of 46 feet?
Fittoniya [83]

Answer:

23 Seconds

The roach is going 2 feet per second so you can split the amount of feet in half because he will go the same distance 2 times as fast.

5 0
3 years ago
Mr. Ramirez orders drumsticks and sheet music for a group of students. One pair of drumsticks costs $1. 50, and the sheet music
diamong [38]

Answer:

Step-by-step explanation:

It expresses how much money he had to pay in total for the sheet music and drumsticks altogether.

Have an amazing day!

Please mark brainliest!

8 0
2 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Hii i need help! write the inequality represented by the graph below.
pentagon [3]
95252226!!
0363373
44448
7 0
2 years ago
HELPPPPP MEEEEE :((((
lutik1710 [3]

Answer:

B) 75, 3

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST I REALLY WANT TO LEVEL UP

8 0
2 years ago
Read 2 more answers
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