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2 years ago

Which of the following is a solution of x2 + 2x + 4?

Mathematics

2 answers:

scoray [572]2 years ago

3 0

Answer:8x

Step-by-step explanation:

2++2=4 add x up 4 = 8x

svetlana [45]2 years ago

3 0

Do you mean 2x for the first term or x^2? If the first term is 2X then the solution would be 4x+4. If the first term is not 2x but x^2 instead, then there is no solution for it

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What is the value of x in the equation x - y = 30, when y = 15?<br> O4<br> O 8<br> O 80<br> O 200

olganol [36]

$\frac{1}{5}x - \frac{2}{3} y = 30 \\$

Putting the value of Y = 15

$\frac{1}{5} x - \frac{2}{3} \times 15 = 30 \\ \frac{1}{5} x = 30 + 10 \\ \frac{1}{5} x = 40 \\ x = 5 \times 40 \\ x = 200$

So, X = 200

6 0

2 years ago

A random sample of 100 automobile owners in thestate of Virginia shows that an automobile is driven onaverage 23,500 kilometers

Anastaziya [24]

Answer:

a) 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

Step-by-step explanation:

Given that:

Mean (μ) = 23500 kilometers per year

Standard deviation (σ) = 3900 kilometers

Confidence level (c) = 99% = 0.99

number of samples (n) = 100

a) α = 1 - c = 1 - 0.99 = 0.01

$\frac{\alpha }{2} =\frac{0.01}{2}=0.005\\ z_{\frac{\alpha }{2}}=z_{0.005}=2.57$

Using normal distribution table, $z_{0.005$ is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.

The margin of error (e) is given as:

$e= z_{0.005}\frac{\sigma}{\sqrt{n} } = 2.57*\frac{3900}{\sqrt{100} } =1002.3$

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) = (22497.7, 24502.3)

Confidence interval = 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

5 0

3 years ago

Please help me! I’ll give Brainliest to the correct answer!!

sveta [45]

The answer will be 0

4 0

3 years ago

If a 100-part spinner is spun, and then a coin is flipped, how many possible outcomes are in the sample space for the compound e

Inessa [10]

Answer:

200

Step-by-step explanation:

3 0

3 years ago

Alex purchased a new car for $28000. The car depreciates 7.25% each year. what will the price be in 5 years?

dalvyx [7]

Use the depreciation formula.

$\sf p(1-r)^n$

Where 'p' is the principal value, 'r' is the rate it depreciates, and 'n' is the time. Just plug in what we know:

$\sf 28000(1-0.0725)^5$

Simplify by subtracting:

$\sf 28000(0.9275)^5$

Simplify the exponent:

$\sf 28000(0.6864)$

Multiply:

$\sf\approx\boxed{\sf\$ 19219.20}$

8 0

3 years ago