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Lina20 [59]
3 years ago
13

Which combination will produce a precipitate? Which combination will produce a precipitate? KOH (aq) and HNO3 (aq) AgC2H3O2 (aq)

and HC2H3O2 (aq) Pb(NO3)2 (aq) and HCl (aq) Cu(NO3)2 (aq) and KC2H3O2 (aq) NaOH (aq) and Sr(NO3)2 (aq)
Chemistry
1 answer:
crimeas [40]3 years ago
7 0

Explanation:

A precipitate is defined as an insoluble substance that emerges upon mixing of two aqueous solutions.

For example, 2NaOH(aq) + Sr(NO_{3})_{2}(aq) \rightarrow Sr(OH)_{2}(s) + 2NaNO_{3}(aq)

As precipitate is a solid and it is represented by (s). And, an aqueous solution is represented by (aq).

So, the products of the given reactants will be as follows.

KOH(aq) + HNO_{3} \rightarrow KNO_{3}(aq) + H_{2}O(aq)

AgC_{2}H_{3}O_{2}(aq) + HC_{2}H_{3}O_{2}(aq) \rightarrow \text{No reaction}

Pb(NO_{3})_{2}(aq) + HCl(aq) \rightarrow PbCl_{2}(s) + 2HNO_{3}(aq)

Cu(NO)_{3}_{2}(aq) + CH_{3}COOK(aq) \rightarrow Cu(CH_{3}COO)_{2})(aq) + 2KNO_{3}(aq)

2NaOH(aq) + Sr(NO_{3})_{2}(aq) \rightarrow Sr(OH)_{2}(s) + 2NaNO_{3}(aq)

Hence, we can conclude that out of the given options, these two equations will produce a precipitate.

Pb(NO_{3})_{2}(aq) + HCl(aq) \rightarrow PbCl_{2}(s) + 2HNO_{3}(aq)

2NaOH(aq) + Sr(NO_{3})_{2}(aq) \rightarrow Sr(OH)_{2}(s) + 2NaNO_{3}(aq)

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What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?
kirza4 [7]
The question above can be solved by using this equation: 
CAVA =CBVB
Where:
CA =Concentration of acid = 1.0 M
VA = Volume of acid = ?
CB = Concentration of base = 1.0 M
VB = Volume of base = 25 ml
VA = CBVB / CA
VA = [1 * 25] / 1 = 25 / 1 = 25
VA = 25 ml
Therefore, the volume of acid that is required to completely neutralize the base is 25 ml.<span />
8 0
3 years ago
6
Vanyuwa [196]

Answer:

If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the  pressure of the gas decreased by a factor of 3.</em></u>

Explanation:

Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or

P * V = k

To obtain the proportionality factor k you must make the quotient:

k=\frac{V2}{V1} =\frac{6 L}{2 L}

k= 3

This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the  pressure of the gas decreased by a factor of 3.</em></u>

4 0
3 years ago
Calculate the cfse for a d^3 system in an octahedral field in units of ∆_o. In other words, do not enter "∆_o" with your answer.
Rudik [331]

Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q

To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.

[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.

The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.

To learn more about crystal field stabilization energy  visit:brainly.com/question/29389010

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8 0
1 year ago
How did he know that the nucleus was positively charged?
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'cause alphe-particle which was +ve charge, get repulsion from the atom, so he deducted that.......
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In Atomic Absorption Spectrophotometry, narrow atomic lines are desirable. However, line broadening arises from: (a) Jablonski e
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Line broadening in AAS, arises due to some effects, which can occur due to a number of factors. The line width broadening effects include: Doppler, Lorentz, Self absorption, and quenching effects.

Doppler effect arises because along the line of observation, atoms will have different components of velocity.

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