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alexdok [17]
3 years ago
8

Which is a compound? A. sodium B.sugarC. nitrogen D air​

Chemistry
2 answers:
Gelneren [198K]3 years ago
8 0

~H~e~l~l~o~! ☺

<h2>WHAT IS A COMPOUND ?</h2><h2></h2>

ᴛʜᴇ ᴀɴꜱᴡᴇʀ ᴛᴏ ᴛʜɪꜱ ɪꜱ :

~S~o~d~i~u~m~.

ʙᴇᴄᴀᴜꜱᴇ ꜱᴏᴅɪᴜᴍ ɪꜱ ᴀ ᴄᴏᴍᴘᴏᴜɴᴅ.

Hope It Helped!

And Tell me if The answer is wrong . . .

<h2><u>Good Luck With Your Assignment!</u></h2><h2><u></u></h2>

#LearnWithBrainly

~A~n~s~w~e~r~ :

ᴊᴀᴄᴇ ノシ

sleet_krkn [62]3 years ago
5 0

Answer:

d. air

Explanation:

air is composed of two or more elements

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An example of a secondary alcohol is *
mojhsa [17]

Answer:

The answer to your question is the letter B

Explanation:

I will draw the skeletal structures of these compounds to determine which alcohol is secondary.

Secondary alcohol is alcohol in which the hydroxyl group is attached to a secondary alcohol.

Letter A has primary and secondary alcohol so I discard this choice.

Letter B has secondary alcohol, so this is the correct choice.

The letter C has a primary and 2 secondary alcohols so I discard this choice.

5 0
4 years ago
18-19. If a sample for spectrophotometric analysis is placed in a 10-cm cell, the absorbance will be 10 times greater than the a
miss Akunina [59]

Answer:

As long as it is a blank solution of the reagent, the Absorbance will be 0 regardless of the path length.

Explanation:

Absorbance of light by a reagent of concentration c, is given as

A = εcl

A = Absorbance

ε = molar absorptivity

c = concentration of reagent.

l = length of light path or length of the solution the light passes through.

So, if all.other factors are held constant, If a sample for spectrophotometric analysis is placed in a 10-cm cell, the absorbance will be 10 times greater than the absorbance in a 1-cm cell.

But the reagent blank solution is called a blank solution because it lacks the given reagent. A blank solution does not contain detectable amounts of the reagent under consideration. That is, the concentration of reagent in the blank solution is 0.

Hence, the Absorbance is subsequently 0. And increasing or decreasing the path length of light will not change anything. As long as it is a blank solution of the reagent, the Absorbance will be 0 regardless of the path length.

Hope this Helps!!!

5 0
3 years ago
The weak base ionization<br> constant (Kb) for HCO3 is<br> equal to:
hammer [34]

Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.

<h3>What is a weak base ionization constant?</h3>

The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.

The reaction for HCO₃ is given as:

HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O

The value of Ka for the given reaction will be:

Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]

Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.

Learn more about the weak ionization constant here:

brainly.com/question/27200344

#SPJ1

8 0
2 years ago
Explain how carbon’s bonding ability makes it unique.
STatiana [176]

\huge\fcolorbox{red}{pink}{Answer ♥}

The carbon atom is unique among elements in its tendency to form extensive networks of covalent bonds not only with other elements but also with itself. ... Moreover, of all the elements in the second row, carbon has the maximum number of outer shell electrons (four) capable of forming covalent bonds.

Hope it helps uh ✌️✌️✌️

Gud mrng

7 0
3 years ago
To determine the concentration of an EDTA solution, 4.11 g of Zn metal was used. The volume of EDTA solution needed to reach the
USPshnik [31]

Answer:

2.23M

Explanation:

Molarity of a solution is calculated thus

Molarity = number of moles (n) ÷ volume (V)

According to this question, 4.11g of Zn metal was used in order to reach a volume of EDTA solution of 28.26 mL.

28.26mL = 28.26/1000

= 0.02826L

Using mole = mass/molar mass to calculate no. of moles of Zn

Mole = 4.11/65.4

mole = 0.0628mol

Molarity = 0.0628 ÷ 0.02826

Molarity = 2.23M

The concentration of the EDTA solution used is 2.23M

7 0
3 years ago
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