Answer:
Explanation:
From the given information;
Let Q(t) = mass of dye in the tank as a function of time
The mass in the tank = 200 L × (1g/L) = 200 g
Using the law of mass conservation;
Q(0) = 200
By finding the solution to the ODE using the method of separation of variables;
Using the initial condition;
200 = Q(0) = C
1% of 200g = 2g of dye solution
∴
t = 460.5 hours
Answer:
2 Cu2O + C → 4 Cu + CO2
This is an oxidation-reduction (redox) reaction:
4 CuI + 4 e- → 4 Cu0 (reduction)
C0 - 4 e- → CIV (oxidation)
Cu2O is an oxidizing agent, C is a reducing agent.
Explanation:
?????
We know, by law of constant proportion :
Chemical compounds always contains its component in constant fixed ratio or in fixed percentage without depend on its source, method of preparation and mass of compound.
Therefore, percentage of oxygen is same for any mass.
Hence, this is the required solution.