Can anybody help me

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

17 x 0.52= 8.84
Hope This Helps

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Find the area I will make you Brainliest (show working) the bottom number is 8 cm where it says liveworksheets

ki77a [65]

Answer:

228cm^2

Step-by-step explanation:

Multiply 18cm by 10cm:

18 x 10 = 180cm^2

So we have the area of the biggest/top part: 180cm^2

For the bottom part:

You've said the length of the bottom side is 8cm.

We know the length of the biggest side: 24cm. And we know the length of the opposite side: 18cm. So, to find the length of the missing side, it's simple subtraction:

24cm - 18cm = 6cm

So now we have lengths for 2 sides: 8cm and 6cm.

Multiply these to give the area:

8cm * 6cm = 48cm^2

Add these areas of both shapes together to give total area:

180cm^2 + 48cm^2 = 228cm^2

8 0

3 years ago

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim

geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

$\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i$

$[a, b] = [-8, 6]$

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x$

Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$