To get the 0.12 to repeat, the trick is to subtract 1 from the denominator
Then reduce the fraction.
now add the 3 to get
Add 13 to both sides, which leaves you with k=42.
Complete question is;
Mia is tracking her savings account balance. She knows the equation y = 8000p^(t) can be used to find her balance y in any year t, but she can't remember what p represents. Her balance 3⅔ years after opening her account, is $9,905.54. What is the value of p?
Answer:
p = 1.06
Step-by-step explanation:
We are told that the equation y = 8000p^(t) can be used to find her balance y in any year t.
Now, we are given t = 3⅔ = 11/3 years
Also, we are given balance after 11/3 years as;
y = $9,905.54
Thus;
Plugging the relevant values into y = 8000p^(t), we have;
9,905.54 = 8000p^(11/3)
p^(11/3) = 9905.54/8000
p = (9905.54/8000)^(3/11)
p = 1.06
637 is the answer because our value is 980 we all know the unknown value with x for the step above 980 and 100% and 65% is the result in a pair of a simple equations
hi
1st draw: green
2/12. (2 green out of 12 marbles), reduces to 1/6
2nd draw: blue
4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)
Probability of theses BOTH happening: multiply these individual probabilities.
Conditional probability:
P(a and b) = P(a)P(b|a)
Prob(event 1) × Prob(event 2 given event 1).
1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.
