Answer:
Top right is QI, top left is QII, bottom left is QIII, bottom right is QIV
Step-by-step explanation:
the quadrants start with one at the top left and rotate counterclockwise, rotate to the left
Answer:
Step-by-step explanation:
Ok, so the slope has to be the same because it’s parallel.
y=2/3x+1
slope=2/3
y=-2
x=-5
y=2/3x+ what
-2=-3 1/3 + what
1 1/3
hence, y=2/3x+4/3
D. 75 cm
Step-by-step explanation:
fill in the y with 20.5, so you get 20.5=0.3x-2. Add the 2 to the 20.5 so you get 22.5=0.3x. Divide both by 0.3 to get 75=x.
sorry if it's a bd explanation, hope this helps :)
1.
Calculate the sum
5x - 10 + 7 = 65 - 20x + 32
Move terms
5x - 3 = 97 - 20x
Collect the like terms and calculate
5x + 20x = 97 +3
Divide both sides by 25
25x = 100
X= 4 ANSWER
I skipped some steps because it would be too long :/
2.
Multiply parenthesis by 8
20x>8(4x - 5) -20
Calculate
20x>32x - 40 - 20
Move variable to the left
20x>32x-60
Collect like terms
20x - 32x > -60
Divide both sides by -12
-12x>-60
X<5 ANSWER
The distance of the ball from the foot of the tower is : 35.18m
The ball would be moved 57.2m away from the foot of the tower for the Angle of elevation to be halved.
<h3>What is angle of elevation?</h3>
Angle of elevation is the angle formed between the horizontal and the line of view from the vertical.
Analysis:
The height of the tower and the distance of the ball from the foot of the tower form a right angle triangle.
so we use trigonometry.
a) let distance of the ball from foot of tower be x.
so that, tan 52 = 45/x
x = 45/tan52
x = 45/1.279 = 35.18m
b) let the distance of the ball in the new position from the foot of the tower be y.
if the angle of elevation is halved, then new angle is 52/2 = 26°
tan 26 = 45/y
y = 45/tan26 = 45/0.487 = 92.4m
distance moved from old position to new position = 92.4 - 35.18 = 57.2m
In conclusion, the distance of the ball from the foot of the tower and the distance the ball should move to make its elevation 26° are 35.18m and 57.2m respectively.
Learn more about angle of elevation: brainly.com/question/88158
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