7.5
thats the answer i got for this
Answer:
new image should be 4 x 8
post the pictures for the questions
Step-by-step explanation:
If my answer is incorrect, pls correct me!
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-Chetan K
Answer:
x₁ = (1 + √43)/6
x₂ = (1 - √43)/6
Step-by-step explanation:
6x² - 2x = 7
6x² - 2x - 7 = 0
Formula
ax² + bx + c = 0
a = 6 ; b = - 2 ; c = - 7
x₁/₂ = [-b ± √(b²- 4ac)]/2a
x₁/₂ = (2 ± √4 + 4×6×-7)/12
x₁/₂ = (2 ± √172)/12
x₁/₂ = (2 ± 2√43)/12
x₁/₂ = 2(1 ± √43)/12
x₁/₂ = (1 ± √43)/6
x₁ = (1 + √43)/6
x₂ = (1 - √43)/6
1) We can determine by the table of values whether a function is a quadratic one by considering this example:
x | y 1st difference 2nd difference
0 0 3 -0 = 3 7-3 = 4
1 3 10 -3 = 7 11 -7 = 4
2 10 21 -10 =11 15 -11 = 4
3 21 36-21 = 15 19-5 = 4
4 36 55-36= 19
5 55
2) Let's subtract the values of y this way:
3 -0 = 3
10 -3 = 7
21 -10 = 11
36 -21 = 15
55 -36 = 19
Now let's subtract the differences we've just found:
7 -3 = 4
11-7 = 4
15-11 = 4
19-15 = 4
So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.
3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2
