Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(-2,4) & B(0,-6) Given
A(x₁,y₁) & B(y₂,y₁)
AB =√[(0-(-2))²+(-6-4)²] =√(104) = 10.198 ≈ 10.2
Answer:
D' (1, 3)
Step-by-step explanation:
When reflected across the y = x line, the "x" and "y" coordinates switch.
If D is (3, 1), then:
x = 3
y = 1
Switch the "x" and "y" values, and rewrite as (x, y).
x = 1
y = 3
D' (1, 3)
-2
y2-y1/x2-x1
take the y coordinate of the second pair of coordinates and subtract it by the y coordinate of the first pair, then take the x coordinate from the second pair of coordinates and subtract it from the x coordinate from the first pair. then put your answer from the y coordinate over the answer from the x coordinates. 1 - 13 / 8 - 2, then you get -12/6, which simplifies to 2.
Hope this helps :)
