Answer:
In some circumstances these displays may allow the female to observe the performance of males and to evaluate them as potential mates. To elicit displays from a group of males, a female Mallard may swim with her neck outstretched and her head just above the water
Step-by-step explanation:
hope this helps
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
Answer:
1. A(1;5), B(10;23), slope of 2
2. A(10;9), B(4;0), slope of 1.5
3. A(-35/4;6), B(9;-35/6), slope of -2/3
4. A(5;18), B(25,22), slope of 0.2
5. A(2/9;1/3), B(2/3,-1/3), slope of -1.5
Step-by-step explanation:
Substitute values with correct variable and slopemis coefficient of x when x and y-int. are on 1 side, y is on other side and has coefficient of 1. Hope it works!
Answer:
its 2/6
Step-by-step explanation:
Answer:
C: p < 0.01
Step-by-step explanation:
We are given;
Spearman rank Correlation Coefficient: rs = 0.53
sample size: n = 13 pairs
Now, from the table attached, tracing n = 13 and locating a corresponding value of rs = 0.53 which falls in between 0.484 and 0.56. Thus, we can see that p is greater than the nominal significance value of 0.05 but less than 0.01.
Thus, correct answer is p < 0.01
