Answer:
![x=2+\frac{1}{2}\sqrt[]{21}](https://tex.z-dn.net/?f=x%3D2%2B%5Cfrac%7B1%7D%7B2%7D%5Csqrt%5B%5D%7B21%7D)
or

Step-by-step explanation:

Add 21 on both sides.


a=4
b=-16
c=-5
![x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%20%20%7D%7B2a%7D)
![x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)} }{2(4)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-16%29%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B%28-16%29%5E2-4%284%29%28-5%29%7D%20%20%7D%7B2%284%29%7D)
![x=\frac{16\frac{+}{}\sqrt[]{256+80} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B256%2B80%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}\sqrt[]{336} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B336%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B2%5E2%2A2%5E2%2A21%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}2*2\sqrt[]{21} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D2%2A2%5Csqrt%5B%5D%7B21%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}4\sqrt[]{21} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D4%5Csqrt%5B%5D%7B21%7D%20%20%7D%7B8%7D)
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![x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%7D%7B8%7D%2B%5Cfrac%7B4%5Csqrt%5B%5D%7B21%7D%7D%7B8%7D)
![x=2+\frac{1}{2}\sqrt[]{21}](https://tex.z-dn.net/?f=x%3D2%2B%5Cfrac%7B1%7D%7B2%7D%5Csqrt%5B%5D%7B21%7D)
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![x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%7D%7B8%7D-%5Cfrac%7B4%5Csqrt%5B%5D%7B21%7D%7D%7B8%7D%5C%5Cx%3D2-%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B%7B21%7D)
Answer: 15:13
Step-by-step explanation: 7/7=3500
<h2>
1/7=3500÷7=500</h2><h2>
500x3=1500</h2><h2>
1500+700=2200</h2><h2>3500-2200=1300</h2><h2>1500:1300</h2><h2>15 : 13 (if there is a need to simplify the ratio)</h2><h2 />
The +2 would cause a shift of up two on the y-axis. the 2 infront of the x, would cause the graph to narrow. using the point 0 f(x) would be 2 or (0,0) and on g(x) it would be (0,2) using x=3, you would have (3,3) and (3,8)
If these are the given choices of the above problem,
a. one side and one angle are equal.
<span>b.three sides are equal </span>
<span>c.two angles are equal </span>
<span>d. three angles are equal
Two non-right triangles are congruent when B. THREE SIDES ARE EQUAL.
Two triangles are congruent if:
1) All corresponding sides are equal (SSS)
2) A pair of corresponding sides and the included angle are equal (SAS)
3) A pair of corresponding angles and the included side are equal (ASA)
4) A pair of corresponding angles and a non-included side are equal (AAS)</span>
Answer: The bag of candy corn will take 5 seconds to land on the floor and it will hit it with velocity of 49m/s.
Step-by-step explanation: A free falling object has only Gravitational Force acting on it, so acceleration will be due to gravity, which has magnitude
g = 9.8m/s².
As Professor Sosa drops the bag, its initial velocity and time are 0.
The building has a height of 400ft, so adjusting units: y = 121.92 m and
= 0.
For this problem, going down will be the positive reference.
Then:




t ≈ 5
<u>It will take </u><u>5s</u><u> for the candy corn bag to land on the ground.</u>
Acceleration is the change in velocity per change in time, so:

As initial velocity and time are 0 and rearraging it:
v = g.t
v = 9.8*5
v = 49
<u>The bag will hit the ground with </u><u>velocity</u><u> of magnitude </u><u>49 m/s.</u>