Can someone please help me workout this problem? If the quotient obtained by dividing 8x^4 - 2x^2 + 6x - 7 by 2x+1 is equal to 4
x^3 + px^2 - qx +3, then find the remainder and also the values of p and q.
1 answer:
Answer:
The answer to your question is p = -2 q = -6 remainder = -10
Step-by-step explanation:
Data
Dividend = 8x⁴ - 2x² + 6x - 7
Divisor = 2x + 1
Quotient = 4x³ + px² - qx + 3
Process
1.- Divide using long division
4x³ - 2x² + 3
2x + 1 8x⁴ + 0x³ - 2x² + 6x - 7
- 8x⁴ - 4x³
0 - 4x³ - 2x²
+ 4x³ +2x²
0 0 + 6x - 7
-6x - 3
0 - 10 Remainder
px² = -2x² then p = -2
-qx = 6x then q = -6
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Answer:
X = 21/4 - 7/4 = 14/4 = 7/2 = 3 and 1/2
Step-by-step explanation:
X + (2 and 1/2) - 3/4 = 5 and 1/4
X + 2 and 2/4 - 3/4 = 5 and 1/4 <--- common denominator
X + 10/4 - 3/4 = 21/4
X + 7/4 = 21/4
X = 21/4 - 7/4 = 14/4 = 7/2 = 3 and 1/2
Answer:
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
Please give brainliest
Answer:
The slope is "Undefined"
Step-by-step explanation:
Answer:
Factoring in groups is like breaking it apart piece by piece and takes more steps.
Factoring the difference of two squares takes few steps and is easier.
361 + 173 =361+173
(a+b)+(a-b)=361+173
a+b=a-b=534
2a=534
a=267
267+b=361
b=94
the two numbers are 267 and 94
