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Maurinko [17]
3 years ago
10

Please! asap! someone help me.

Mathematics
2 answers:
Musya8 [376]3 years ago
4 0

Answer:

10

is the answer which I know

Allisa [31]3 years ago
3 0

Answer:

10

Step-by-step explanation:

10(4-7)

-------------

-(4-1)

Parentheses first

10(-3)

----------------

-(3)

Cancel the negative 3's

10(1)

------------

(1)

10

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Margaret is thinking of a number. She says, “My number is odd. It is a factor of 36 and a multiple of 3” There are two possible
Novay_Z [31]

Answer:

3,9

Step-by-step explanation:

Factors of 36 = 1,2,3,4,6,9,12,18,36

Those factors which are odd = 1,3,9

Odd Factors which are multiple of 3 = 3,9

So, these are the two numbers Margret might be thinking of.

4 0
4 years ago
I hate copy and pastes​
tangare [24]

Answer:

why they're so helpful

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Answer: 6/2(1+2)=.<br><br><br> explain:
Tcecarenko [31]

Answer:

9

Step-by-step explanation:

6/2(1+2)

6/2(3)

3(3)

9

I hope this helped! If so, please mark brainliest!

8 0
3 years ago
This is not an incomplete question, it has come from a very reliable source, please dont delete. If 60% of the students in Mr. B
nika2105 [10]

Answer:

35 students

Step-by-step explanation:

Take the number of students in the class and multiply by 60% and see if you get an integer number

28 * .60 =16.8  not an integer

32 * .6 =19.2

35 * .6 =21  yes

39*.6 =23.4

7 0
3 years ago
The graph below shows the average Valentine’s Day spending between 2003 and 2012
Lapatulllka [165]
The average rate of change of a graph between two intervals is given by the difference in value of the values on the graph of the two interval divided by the difference between the two intervals.

Part A.

From the graph the average Valentine's day spending in 2005 is 98 while the average Valentine's day spending in 2007 is 120.

The average rate of change in spending between 2005 and 2007 is given by

\frac{120-98}{2007-2005} = \frac{22}{2} =\$11/year



Part B

From the graph the average Valentine's day spending in 2004 is 100 while the average Valentine's day spending in 2010 is 103.

The average rate of change in spending between 2004 and 2010 is given by

\frac{103-100}{2010-2004} = \frac{3}{6} =\$0.5/year



Part C:

From the graph the average Valentine's day spending in 2009 is 102 while the average Valentine's day spending in 2010 is 103.

The average rate of change in spending between 2009 and 2010 is given by

\frac{103-102}{2010-2009} = \$1/year

7 0
4 years ago
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