Let present ages of father be x and of son is y years
x/y = 7/2, 2x=7y, y=2x/7
(y+5)=37/100*(x+5)
(2x/7+5)=37/100*(x+5)
(2x+35)/7=(37x+185)/100
200x+3500=259x+1295
259x-250x=3500-1295
59x=2205
x=37.37 years
Answer:
letter c
Step-by-step explanation:
.............
I think it's the third one b/c
the associative property states that it doesn't matter how you group the
numbers in parenthesis in addition.
Answer:
a. x=600
b. y=60
c. x = 150 and y = 45
Step-by-step explanation:
0.25x+2.50y=150
Answer:
-36/15
Step-by-step explanation:
If the indefinite integral of f(x)dx is F(x), then your integral from 1 to 5 is ...
F(5) -F(1) = 36/15
The integral in the reverse direction is ...
F(1) -F(5) = -(F(5) -F(1)) = -36/15