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Sergeeva-Olga [200]
3 years ago
10

How to find interval of interest of objective function?

Mathematics
1 answer:
Julli [10]3 years ago
3 0
The interval of interest for your objective function depends on your optimization problem.
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How do I say this number 51,634,703,001
olasank [31]
Fifty one billion six hundred thirty four million seven hundred three thousand and one
6 0
3 years ago
Carter answered 5% of the questions
Ipatiy [6.2K]

Answer:19/20

1-20=19

1÷20=0.05

0.05=5%

I hope this is good enough:

4 0
3 years ago
If three quarters of a number decreased by twenty is equal to eighty two, what is that number?
Studentka2010 [4]

A number is :

x

_________________________________

Three quarters of it means :

\frac{3}{4}x \\

_________________________________

Decrease by 20 means :

\frac{3}{4}x - 20 \\

_________________________________

Equals to 82 means :

\frac{3}{4}x - 20 = 82 \\

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What is that number ?

x asked so we must solve the above equation for x.

Let's do it....

\frac{3}{4}x - 20 = 82 \\

Plus sides 20

\frac{3}{4}x = 82 + 20 \\

\frac{3}{4}x = 102 \\

Multiply sides by 4

3x = 102 \times 4

Divided sides by 3

x =  \frac{102 \times 4}{3} \\

x =  \frac{102}{3} \times 4 \\

Simplify

x = 34 \times 4

x = 136

So that number is 136 .

_________________________________

And we're done.

Thanks for watching buddy good luck.

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5 0
3 years ago
An objects weight on Mars is 38% of its weight on Earth. If an object weighs p, pounds on Earth, write an expression for its wei
oksano4ka [1.4K]

0.38p

To get the percent of something, you turn the percent to a decimal and multiply it to the number.

Here, we want the expression to get 38% of p. So we turn 38% to 0.38 and multiply it to p. Since we don't know what p is, we have to leave it as 0.38p

The answer is 0.38p


Hope this helps!

3 0
3 years ago
Read 2 more answers
16x-5y=-33 solve the equation
LUCKY_DIMON [66]
 16x - 5y = -33               First, you subtract 16x from both sides of the 
<u>-16x           -16x       </u>      equation
         <u>-5y</u> = <u>-16x -33</u>       Next, you divide both sides of the equation by -5 to 
          -5          -5            make "y =" form
            y = 16/5x + 33/5
3 0
3 years ago
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