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2 years ago

The diameter of a circle is 10 cm. Find its area in terms of π.

Mathematics

2 answers:

katovenus [111]2 years ago

8 0

Answer:

A = 25 $\pi$ $cm^{2}$ or A = 78.54 $cm^{2}$

Step-by-step explanation:

The diameter of a circle is just the radius two times, in this case, the diameter is 10. This means that the radius would be 5. Therefore we can use 5 as our r variable in the formula for area (A= $\pi r^{2}$ ),

A = $\pi 5^{2}$ , simplify $5^{2}$ :

A = 25 $\pi$

From here you can leave the asnwer in its excat form, 25 $\pi$ , or you can simplify it by multiply 25 times pi to get 78.54 (rounded to the hundreths place).

lutik1710 [3]2 years ago

3 0

Answer:

7.9577cm^2

Step-by-step explanation:

10 = 2 * r * pi

==> r = 5/pi

area = r * r * pi = 25/pi = 7.9577cm^2

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One half the sum of a number z and 3 1/2 is 4 1/2

solong [7]

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3 years ago

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spayn [35]

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3 years ago

Read 2 more answers

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scoundrel [369]

Answer:

x=-3,x=9

Step-by-step explanation:

x^2-6x-20-7=0

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4 0

3 years ago

7x2x2x2 is the prime factorization for which of the following

GaryK [48]

Answer: B) 56

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3 0

3 years ago

One year had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at

lord [1]

Answer:

Thomas had the better year relative to their peers.

Step-by-step explanation:

<u>The complete question is</u>: One year Thomas had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.31. Also, Karla had the lowest ERA of any female pitcher at the school with an ERA of 3.02. For the males, the mean ERA was 4.837 and the standard deviation was 0.541. For the females, the mean ERA was 4.533 and the standard deviation was 0.539. Find their respective z-scores. Which player had the better year relative to their peers, or ? (Note: In general, the lower the ERA, the better the pitcher.)

We are given that for the males, the mean ERA was 4.837 and the standard deviation was 0.541. For the females, the mean ERA was 4.533 and the standard deviation was 0.539.

As, we know that the z-score is calculated by the following formula;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean

$\sigma$ = standard deviation

Now, firstly we will calculate the z score for Thomas;

z-score = $\frac{X-\mu}{\sigma}$

= $\frac{3.31-4.837}{0.541}$ = -2.823

{Here, the mean ERA for the males was 4.837 and the standard deviation was 0.541}

Similarly, we will calculate the z score for Karla;

z-score = $\frac{X-\mu}{\sigma}$

= $\frac{3.02-4.533}{0.539}$ = -2.807

{Here, the mean ERA for the females was 4.533 and the standard deviation was 0.539}

Now, it is stated in the question that the lower the ERA, the better the pitcher.

So, we can clearly see that Thomas had a lower ERA of z-score as -2.823 < -2.807. This means that Thomas had the better year relative to their peers.

5 0

3 years ago