Answer:
9 Model As.
Step-by-step explanation:
Let A represent Press A and let B represent Press B.
So, they own 14 total presses. This means that:

They can print 905 books per day, in other words, since A prints 70 per day and B prints 55 per day:

This is now a system of equations. Solve by substitution. From the first equation, subtract B from both sides:

Substitute this into the second equation: "

First, we can divide everything by 5 to simplify things:

Distribute the left:

Combine like terms:

Subtract 196 from both sides:

Divide both sides by -3

So, the company has 5 Model B presses.
Which means that the company has 14-5 or 9 Model A presses.
And we're done!
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
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Answer:
<u>7y +2x</u>
Let x = the number of weeks
Hope this helps!
Answer:
Step-by-step explanation: