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Brrunno [24]
3 years ago
7

if waves on the lake have a frequency of 3 hertz and a wavelength of 4 meters,what is the speed of the waves?

Chemistry
1 answer:
AlexFokin [52]3 years ago
5 0
You have to use the equation v=λf
v is the velocity of the wave
λ is the wave length of the wave (how far the wave goes in one cycle)
f is the frequency of the wave (how long one cycle is) 

V=4m×3Hz
v=12m/s

Hz stands for s⁻¹ which is why the final units is m/s

I hope this helps.  Let me know if anything is unclear.

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Which statement below is the BEST explanation for the differences
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Answer:

A

Explanation:

Electron geometry describes the arrangement of electron groups. Molecular geometry describes the arrangement of atoms, excluding lone pairs.

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3 years ago
Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
3 years ago
The pressure on a 200-milliliter sample of CO2(g) at
motikmotik

Answer:

A) 100 mL

Explanation:

At constant temperature and number of moles, Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 200 mL

V₂ = ?

P₁ = 60 kPa

P₂ = 120 kPa

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{60\ kPa}\times {200\ mL}={120\ kPa}\times {V_2}

{V_2}=\frac{{60}\times {200}}{120}\ mL

{V_2}=100\ mL

3 0
3 years ago
Is lithium ionization energy high low or medium?
satela [25.4K]
It’s soft which makes It low energy
6 0
3 years ago
Read 2 more answers
The air in a 2 L balloon at 0.998 atm and 34.0 °C. What will be its pressure if it is brought to a higher altitude where it now
Phantasy [73]

Answer: 0.529 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.998 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2 L

V_2 = final volume of gas = 3.5 L

T_1 = initial temperature of gas = 34.0^oC=273+34.0=307.0K

T_2 = final temperature of gas = 12.0^oC=273+12.0=285.0K

Now put all the given values in the above equation, we get:

\frac{0.998\times 2}{307.0K}=\frac{P_2\times 3.5}{285.0K}

P_2=0.529atm

Thus the pressure if it is brought to a higher altitude where it now occupies 3.5 L and is at 12.0 °C is 0.529 atm

4 0
4 years ago
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