Answer:
19.3 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 12.4 kg
Volume (V) = 642 mL.
Density (D) =.?
Next, we shall convert 12.4 kg to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
12.4 kg = 12.4 × 1000
12.4 kg = 12400 g
Therefore, 12.4 kg is equivalent to 12400 g.
Finally, we shall determine the density of the gold as follow:
Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) / volume (V)
D = m/V
With the above formula, the density of gold can easily be obtained as follow:
Mass (m) = 12400 g
Volume (V) = 642 mL.
Density (D) =.?
D = m/V
D = 12400/642
D = 19.3 g/mL
Therefore, the density of hold is 19.3 g/mL
At 218 °C, solid NH₄SH decomposes to form 0.011 M NH₃ and H₂S, as given by its equilibrium constant.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant (Keq) is the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants, all raised to their stoichiometric coefficients.
Only gases and aqueous species are included.
- Step 1. Make an ICE chart.
NH₄SH(s) ⇋ NH₃(g) + H₂S(g)
I 0 0
C +x +x
E x x
- Step 2. Write the equilibrium constant.
Keq = 1.2 × 10⁻⁴ = [NH₃] [H₂S] = x²
x = 0.011 M
At 218 °C, solid NH₄SH decomposes to form 0.011 M NH₃ and H₂S, as given by its equilibrium constant.
Learn more about equilibrium here: brainly.com/question/5081082
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If you want both answers, its D and C because luster is how light reflects off the mineral, and a renewable resource is something that can be renewed as much as it was used.
Answer:
A strong acid completely ionizes in water.
