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Lorico [155]
2 years ago
9

calculate δg o for each reaction using δg o f values: (a) h2(g) i2(s) → 2hi(g) 2.6 kj (b) mno2(s) 2co(g) → mn(s) 2co2(g) kj (c)

nh4cl(s) → nh3(g) hcl(g) 91.2 kj standard thermodynamic values at 298 k substance δg o f (kj/mol) co(g) −137.2 co2(g) −394.4 co2(aq) −386.2 hcl(g) −95.30 hcl(aq) −131.17 hi(g) 1.3 mno2(s) −466.1 nh3(g) −16 nh3(aq) 26.7 nh4cl(s) −203.0
Chemistry
1 answer:
Reika [66]2 years ago
6 0

(a)The change in Gibbs free energy for the reaction has been 2.6 kJ/mol.

(b) The change in Gibbs free energy for the reaction has been -49.3 kJ/mol.

(c) The change in Gibbs free energy for the reaction has been 91.38 kJ/mol.

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Answer:

THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO

Explanation:

The steps involved in calculating the empirical formula of this substance in shown in the table below:

Element                            Carbon           Hydrogen          Nitrogen         Oxygen

1. % Composition              40.66              8.53                 23.72                27.09

2. Mole ratio =

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                                       =  3.3883            8.53              1,6943             1.6931

3. Divide by smallest

value (0.6931)          3.3883/1.6931    8.53/1.6931    1.6943/1.6931   1.6931/1.6931

                               =      2.001                  5.038           1.0007                      1

4. Whole number ratio        2                       5                   1                               1

The empirical formula = C2H5NO

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\huge{ \underline{ \boxed{ \bf{ \green{Answer:}}}}}

Inside the stomach, Hydrochloric acid kills micro-organisms in the food. Stomach juices begin to break down <u>proteins</u> to amino acids.

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