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zhuklara [117]
3 years ago
6

Elements in which the d-sublevel is being filled have the properties of

Chemistry
2 answers:
andre [41]3 years ago
7 0

Elements in which the d-sublevel is being filled have the properties of;

<em><u>transition metals. </u></em>

In quantum theory the sublevel is an energy level. Now, the d-sublevel in atomic configuration has 5 orbitals and as such can contain a maximum of 10 electrons.

Now, this d-sublevel is used primarily by elements called "transition elements" as they are also called d-block elements.

However, these transition elements are also called transition metals because all the transition elements possess properties of metals generally.

In conclusion, elements in which the d-sublevel is being filled have the properties of transition metals.

Read more at; brainly.com/question/3948476

Nadya [2.5K]3 years ago
4 0

Answer:

Elements in which the d-sublevel is being filled have the properties of metals

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Flow-duration data are daily mean flow values measured over a specified time interval that have been exceeded various percentages of the specified time interval.

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A 30.5-g sample of water at 300. K is mixed with 48.5 g water at 350. K. Calculate the final temperature of the mixture assuming
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3 0
3 years ago
A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m
kogti [31]

Answer:

The molar mass of the unknown gas is \mathbf{ 51.865 \  g/mol}

Explanation:

Let assume that  the gas is  O2 gas

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Under the same conditions;

the same number of moles of an unknown gas requires  time t₂  =  6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

R \  \alpha  \ \dfrac{1}{\sqrt{d}}

R = \dfrac{k}{d}  where K = constant

If we compare the rate o diffusion of two gases;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}

Since the density of a gas d is proportional to its relative molecular mass M. Then;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}

Rate is the reciprocal of time ; i.e

R = \dfrac{1}{t}

Thus; replacing the value of R into the above previous equation;we have:

\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}

We can equally say:

{\dfrac{t_2}{t_1}}=  {\sqrt{\dfrac{M_2}{M_1}}

{\dfrac{6.34}{4.98}}=  {\sqrt{\dfrac{M_2}{32}}

M_2 = 32 \times ( \dfrac{6.34}{4.98})^2

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M_2 = 32 \times 1.62076418

\mathbf{M_2 = 51.865 \  g/mol}

7 0
3 years ago
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