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Karo-lina-s [1.5K]
2 years ago
10

What is the area of a rectangle with a lenght of 12 inches and a width of 3 inches

Mathematics
2 answers:
Phoenix [80]2 years ago
5 0

Answer:

36

Step-by-step explanation:

area of a rectangle is length x width, so 12 x 3 = 36

3241004551 [841]2 years ago
4 0
36 inches. Basexheight. 12x3=36
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A circle is centered at J(3, 3) and has a radius of 12.
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Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

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3 years ago
Correct Answer Will get Brainliest
Tanya [424]

Answer:48.6

we know that

You can paint 75 square feet of a surface every 45 minutes

so

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45(81)/75=48.6

hope this helped and I hope you get a correct answer :D

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Answer: I need more evindence to answered it but I say its the third one

Step-by-step explanation:

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