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3 years ago

PLZ CAN SOMEONE ANSWER THIS !!

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

5 0

Answer:

(-4,2)

Step-by-step explanation:

First we have to find a common multiple to use to add and find the system of equations. We need to eliminate one of the variables in order to solve.

Since 5 * 3 = 15, and 3 * -5 = 15, -15x and 15x will cancel each other out. Therefore x will be eliminated.

Before:

5x + 2y = -16

3x + 7y = 2

After:

15x + 6y = -48 <----------Now we solve for y

-15x + -35y = -10

+----------------------

-29y = -58

-29 -29

y = 2

Now what we do is we choose and equation and solve for x, since it is still unknown. Any equation is fine but I will choose the second one since it has easy numbers.

3x + 7y = 2

3x + 7(2) = 2

3x + 14 = 2

-14 -14

----------------------

3x = -12

3 3

x = -4

Therefore our final answer is (-4,2)

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Use the triangle below to find cos V.

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Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

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$cos V= \frac{TV}{UV}$

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Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

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8 0

2 years ago

PLEASE ANSWER!!!!!! REALLY IMPORTANT

faust18 [17]

Answer-

The height of the prism is 6 units

Solution-

As the base of the prism is a hexagon consisting of 2 congruent isosceles trapezoids.

So,

$V_{Prism}=Area_{Base}\times Height$

And,

$Area_{Base}=2\times \text{Area of the trapezoid}$

Also,

$\text{Area of the trapezoid}=\dfrac{1}{2}\times \text{Height}\times (\text{Sum of two parallel lines})$

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Putting all the values,

$V_{Prism}=2\times \dfrac{39}{2}\times Height=39\times Height$

As the volume is given, so

$\Rightarrow 39\times Height=234$

$\Rightarrow Height=\dfrac{234}{39}=6$

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