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3 years ago

The area of a square painting is 81p^2+90p+25 what is the side length of the paining

Mathematics

1 answer:

IgorLugansk [536]3 years ago

5 0

81p²+90p+25=(9p)²+2*9p*5+5²=(9p+5)²
so the side length of the paining is 9p+5

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A salesperson receives a 2.5% commission on sales, what commission does the salesperson receive for $8,000 in sales

Tcecarenko [31]

Percentage of commission received by the salesperson = 2.5%
Amount of sales made by the salesperson = $8000
Then
The amount of commission received by the salesperson = (2.5/100) * 8000 dollars
= 2.5 * 80 dollars
= 200 dollars
So the salesperson receives a commission of $200 on the total sales made. I hope the procedure is clear enough for you to understand. You can use this method in future for solving similar problems without requiring any help from outside.

7 0

3 years ago

The combined perimeter of the rectangle and triangle is 63 inches. The model shows the dimensions of the rectangle. What is the

katrin2010 [14]

*See diagram in the attachment

Answer:

27 inches

Step-by-step explanation:

Combined perimeter = perimeter of rectangle + perimeter of triangle = 63 inches

Perimeter of rectangle = 2(L + W)

L = 11 in.

W = 7 in.

Perimeter of rectangle = 2(11 + 7) = 36 in.

Let perimeter of the triangle be represented by x

Therefore:

36 + x = 63

Subtract 36 from each side

x = 63 - 36

x = 27

Perimeter of triangle = 27 inches

7 0

3 years ago

Corbin made a scale model of the San Jacinto Monument. The monument has an actual height of 604 feet. Corbins model used a scale

sergejj [24]

Answer: 6.04 inches

Step-by-step explanation:

Given: The actual height of the monument = 604 feet

The scale used by Corbins is 1 inch = 100 feet

It implies in Corbins model 1 feet $=\frac{1}{100}\ inches$

Therefore, The height of the Corbins model in inches= $\frac{604}{100}=6.04\ inches$

Hence, the height of the Corbins model in inches= 6.04 inches

8 0

3 years ago

Verify the identity: (a^2+b^2)(x^2+y^2)=(ax-by)^2+(bx+ay)^2

const2013 [10]

(ax-by)²+(bx+ay)²
a²x²-2axby+b²y²+b²x²+2axby+a²x²
a²x²+b²x²+b²y²+a²x²
(a²+b²)x²+(a²+b²)y²
(a²+b²)(x²+y²)

8 0

3 years ago

the scale of map is 1cm to 8km , two towns are 52km apart . how far apart are the two towns on the map

posledela

Answer:

6.5 cm

Step-by-step explanation:

The solution to the question above is solved in the attached picture.

6 0

3 years ago