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Maksim231197 [3]
4 years ago
11

Factor the expression completely.

Mathematics
1 answer:
navik [9.2K]4 years ago
4 0

Answer:

(2n + 7) (2n +7)

Step-by-step explanation:

To solve this problem we need to factorize 4n^2 + 28n +49 as shown below

4n^2 + 28n +49\\=>4n^2 + 14n + 14n +49\\=>2n(2n  + 7)  + 7(2n +7)\\=> (2n + 7) (2n +7)

thus, after factorization we see that first option is correct one

(2n + 7) (2n +7)

we can validate this by expanding it

2n (2n +7) + 7 (2n+7)\

=> 4n^2 + 14n + 14n + 49 = 4n^2 + 28n +49 (which is equal to the problem stated expression)

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Please answer this question​
Tems11 [23]

\bold{\huge{\underline{ Solution }}}

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

• \sf{ Polynomial :- ax^{2} + bx + c }

• The zeroes of the given polynomial are α and β .

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

Here, we have polynomial

\sf{ = ax^{2} + bx + c }

<u>We </u><u>know </u><u>that</u><u>, </u>

Sum of the zeroes of the quadratic polynomial

\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}

<u>And </u>

Product of zeroes

\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}

<u>Now, we have to find the polynomials having zeroes </u><u>:</u><u>-</u>

\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}

<u>T</u><u>h</u><u>erefore </u><u>,</u>

Sum of the zeroes

\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}

\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}

\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}

\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}

\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}

\bold{{\dfrac{ -bc - ab}{ac}}}

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

<h3><u>Now</u><u>, </u></h3>

Product of zeroes

\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}

\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}

\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}

\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}

Hence, The product of the zeroes are c/a + a/c + 2 .

<u>We </u><u>know </u><u>that</u><u>, </u>

<u>For </u><u>any </u><u>quadratic </u><u>equation</u>

\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }

\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3><u>Some </u><u>basic </u><u>information </u><u>:</u><u>-</u></h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0
2 years ago
Mnknkknnjkhbjhbkjdesjhajkd1qwbbbbbbbbhbxbhsjhbwqbhzhbwbqbwbhhwqbbhjsqbhswbhhbs
love history [14]

Answer:

mood

Step-by-step explanation:

6 0
3 years ago
What is the constant rate of change shown in the graph
podryga [215]
I would say C instead of A but I am not so sure. 
4 0
3 years ago
Read 2 more answers
Add using scientific notation.<br> (5.2 x 10') + (3.01 x 10^)
satela [25.4K]

Answer: What's the exponents?

Step-by-step explanation:

5.2+3.01=8.21

but then there's no exponents that you stated. So it would be 8.21x10^?

If the tens do have exponents above them, add them together.

I hope this answer helps you!

7 0
4 years ago
(13 POINTS AND BRAINLIEST FOR BEST)
nordsb [41]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Simply multiply 7.25 by 200:

7.25 x 200 = 1450

The actual tower is 1450 feet

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

3 0
3 years ago
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