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Citrus2011 [14]
3 years ago
11

Factor completely 5xy3 + 15x3y2 − 30x2y2. 5(xy3 + 3x3y2 − 6x2y2) 5x(y3 + 3x2y2 − 6xy2) 5xy2(y + 3x2 − 6x) Prime

Mathematics
2 answers:
user100 [1]3 years ago
8 0

Answer:

5xy^2(y+ 3x^2- 6x)

Step-by-step explanation:

5xy^3 + 15x^3y^2 - 30x^2y^2

To factor out an expression, factor out GCF

5xy^3= 5 \cdot x \cdot y \cdot y \cdot y

15x^3y^2= 5 \cdot 3 \cdot x \cdot x \cdot x \cdot y \cdot y

30x^2y^2= 5 \cdot 2 \cdot 3 \cdot x \cdot x \cdot y \cdot y

GCF  is 5 times x times y time y

GCF is 5xy^2. Factor out GCF

5xy^3 + 15x^3y^2 - 30x^2y^2

5xy^2(y+ 3x^2- 6x)

Maslowich3 years ago
4 0

Answer:

5xy^2(y + 3x^2 - 6x).

Step-by-step explanation:

5xy^3 + 15x^3y^2 − 30x^2y^2

The GCF is 5xy^2 so dividing through by this we get the factors:

= 5xy^2(y + 3x^2 - 6x).

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