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3 years ago

Math, yes I don't know if I got it right

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

8 0

Answer:

4*(n)^2

Step-by-step explanation:

yaroslaw [1]3 years ago

5 0

Answer:

3 is the unknow number and the equation is 2+(4*x)=14

Step-by-step explanation:

2+(4*x)=14

2-2)+(4*x)=14 (-2) (subtract both sides)

4x=12

4x=12 (divide both sides)

4 4

x=3

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Find the volume and tell me if cavalieri's principle applies to the figure Need answer ASAP

Volgvan

Where are the numbers or just this? We need numbers like 1 0 6

3 0

3 years ago

Let f(r) = 6, find f-¹(r)

I am Lyosha [343]

There is no answer because there cannot be one to one function inverse.

8 0

1 year ago

How much of a radioactive kind of thorium will be left after 14,680 years if you start with

babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

$N(t)= N_{0}e^{-kt}$

N(t) = amount after the time t

$N_{0}$ = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

$N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t}$ or more simply $N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }$

$t_{h}$ = time of the half-life

We know that $N_{0}$ = 35,912, t = 14,680, and $t_{h}$ =7,340

Plug these into the equation:

$N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }$

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0

2 years ago

Are these functions?

OlgaM077 [116]

Answer:

Relation 1 : Not a function

R2 : Function

R3: Function

R4: Not a function

7 0

3 years ago

Read 2 more answers

A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening night midni

Alex17521 [72]

Answer: It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

Step-by-step explanation:

Since we have given that

n = 84

x = 11

So, $\hat{p}=\dfrac{x}{n}=\dfrac{11}{84}=0.13$

p = 0.20

So, hypothesis:

$H_0:p=\hat{p}\\\\H_a:\hat{p}$

so, test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.13-0.20}{\sqrt{\dfrac{0.2\times 0.8}{84}}}\\\\z=-1.604$

At 1% level of significance, critical value would be

z= 2.58

Since 2.58>-1.604

So, We will accept the null hypothesis.

Hence, It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

4 0

3 years ago

Read 2 more answers