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Maru [420]
3 years ago
6

A single electron can have the following set of quantum numbers: n=3, l=2, ml=0, ms= -1/2.

Chemistry
1 answer:
WINSTONCH [101]3 years ago
6 0

Answer:

True => (3, 2, 0, -1/2) => 3d₀² electron

Explanation:

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A 1.200 liter solution contains 35.0 grams of potassium iodide (KI). What is the molarity of this
enot [183]

Answer:

M = 0.177

Explanation:

First, we have to find the molar mass of potassium iodine (KI).

K = 39.098

I = 126.904

Now, add these values together to get the molar mass of KI

39.098 + 126.904 = 166.0028

Now, it's time to do a grams to moles conversion.

35.0 g KI * \frac{1 mol KI}{166.0028 g KI} = \frac{35.0}{166.0028} = 0.212 mol KI

Now, we can find the molarity of this solution.

Molarity (M) = \frac{mol}{L}

M = \frac{0.212 mol KI}{1.200 L} = 0.177 M

The molarity (M) of this solution is 0.177.

3 0
3 years ago
Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction? carbon + oxygen
frutty [35]
C (solid) + O2 (gas) -> C02 (gas)

6 0
4 years ago
Read 2 more answers
What is the molarity of a solution prepared by diluting 250 mL of a 40% H2SO4 solution to 1 Liter? The density of the stock solu
kiruha [24]

Answer:

1.195 M.

Explanation:

  • We can calculate the concentration of the stock solution using the relation:

<em>M = (10Pd)/(molar mass).</em>

Where, M is the molarity of H₂SO₄.

P is the percent of H₂SO₄ (P = 40%).

d is the density of H₂SO₄ (d = 1.17 g/mL).

molar mass of H₂SO₄ = 98 g/mol.

∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.

  • We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

<em>∴ (MV) before dilution = (MV) after dilution</em>

M before dilution = 4.78 M, V before dilution = 250 mL.

M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.

∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.

3 0
3 years ago
Which hypothesis most likely inspired Leeuwenhoek's experimentation with new technology? If the amount of magnification is corre
Serjik [45]

Answer:

If the amount of magnification is correct, then an individual germ can be seen, because individual germs exist but are too small for human eyes.

Explanation:

<em>Leeuwenhoek was the first scientists to experiment with microorganisms using a self-designed single-lens microscope. He described the tiny organisms as 'animacules'. He is known for his pioneer work in the design of the first microscope.</em>

The microscope works by magnifying objects placed on the stage. Germs are microbes that cannot be seen with ordinary eye unless they are magnified appropriately. They are virtually everywhere, including the parts of the world where humans cannot survive.

Hence, the only correct option which most likely inspired Leeuwenhoek's experimentation with technology is the first option. The remaining options are deficient in some ways.

3 0
4 years ago
When bases dissolve in water they release what type of negative ion?
Leto [7]
A base generally releases a hydroxide ion (OH-) when dissolved in water. 

There are exceptions, such as ammonia NH3, which acts as a base but does not produce OH- ions. There are three definitions of acids and bases (Arrhenius, Bronsted-Lowry, and Lewis) and each one looks at acid/base characteristics differently. OH- donation is the Arrhenius definition.
4 0
4 years ago
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