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EleoNora [17]
3 years ago
7

When bases dissolve in water they release what type of negative ion?

Chemistry
1 answer:
Leto [7]3 years ago
4 0
A base generally releases a hydroxide ion (OH-) when dissolved in water. 

There are exceptions, such as ammonia NH3, which acts as a base but does not produce OH- ions. There are three definitions of acids and bases (Arrhenius, Bronsted-Lowry, and Lewis) and each one looks at acid/base characteristics differently. OH- donation is the Arrhenius definition.
You might be interested in
g Calculate the pOH of a solution that results from mixing 23.3 mL of 0.16 M trimethylamine ((CH3)3N) with 44.1 mL of 0.15 M (CH
hichkok12 [17]

Answer:

pOH = 5.961

Explanation:

To find the pH of a weak base we can use Henderson-Hasselbalch equation for weak bases:

pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]

<em>Where pKb is -log Kb = 4.187 and [] could be taken as moles of each specie.</em>

<em />

<em>Moles (CH₃)₃NHCl:</em>

0.0441L * (0.15mol/L) = 6.615x10⁻³moles

<em>Moles (CH₃)₃N:</em>

0.0233L * (0.16mol/L) = 3.728x10⁻³moles

And pOH is:

pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]

pOH = 4.187 + log [6.615x10⁻³moles] / [3.728x10⁻³moles]

<h3>pOH = 5.961</h3>

<em />

6 0
2 years ago
A 2.0% (w/v) solution of sodium hydrogen citrate, Na2C6H6O7, which also contains 2.5% (w/v) of dextrose, C6H12O6, is used as an
tamaranim1 [39]

Answer:

0.0847M is molarity of sodium hydrogen citrate in the solution

Explanation:

The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.

<em>Moles Na2C6H6O7:</em>

<em>Molar Mass:</em>

2Na: 2*22.99g/mol: 45.98g/mol

6C: 6*12.01g/mol: 72.01g/mol

6H: 6*1.008g/mol: 6.048g/mol

7O: 7*16g/mol: 112g/mol

45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol

Moles of 2g:

2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>

<em />

<em>Liters solution:</em>

100mL * (1L / 1000mL) = <em>0.100L</em>

<em>Molarity:</em>

8.473x10⁻³ moles / 0.100L =

<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
3 0
2 years ago
Read 2 more answers
Fructose-2,6-bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys
postnew [5]

Answer:

1. Increased levels of fructose-2,6-bisphosphatase : Activate gluconeogenesis Inhibit glycolysis

2. Activation of fructose-2,6-bisphosphate (FBPase-2) : Activate glycolysis Inhibit gluconeogenesis

3. Increased glucagon levels : Activate gluconeogenesis Inhibit glycolysis

4. Activation of PFK-2 : Activate glycolysis Inhibit gluconeogenesis

5. Increased levels of CAMP : Activate gluconeogenesis Inhibit glycolysis

Explanation:

Glycolysis is the breakdown of glucose molecules in order to release energy in the form of ATP in response to the energy needs of the cells of an organism.

Gluconeogenesis is the process by which cells make glucose from other molecules for other metabolic needs of the cell other than energy production.

Glycolysis and gluconeogenesis are metabolically regulated in the cell by various enzymes and molecules.

The following shows the various regulatory methods and their effects on both processes:

1. The enzyme fructose-2,6-bisphosphatase functions in the regulation of both processes. It catalyzes the breakdown of the molecule fructose-2,6-bisphosphate which is an allosteric effector of two enzymes phosphofructokinasse-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase-1 which fuction in glycolysis and gluconeogenesis respectively.

Increased levels of fructose-2,6-bisphosphatase  activates gluconeogenesis and inhibits glycolysis by its breakdown of fructose-2,6-bisphosphate.

2. Fructose-2,6-bisphosphate increases the activity of PFK-1 and inhibits the the activity of FBPase-1. The effect is that glycolysis is activated while gluconeogenesis is inhibited.

3. Glucagon is a hormone that stimulates the synthesis of cAMP. It fuctions to activate gluconeogenesis and inhibit glycolysis.

4. Phosphosfructikinase-2, PFK-2 is an enzyme that catalyzes the formation of fructose-2,6-bisphosphate. Activation of PFK-2 results the activation of glycolysis and inhibition of gluconeogenesis.

5. Cyclic-AMP (cAMP) synthesis in response to glucagon release serves to activate a cAMP-dependent protein kinase which phosphorylates the bifunctional protein PFK-2/FBPase-2. This phosphorylation enhances the activity of FBPase-2 while inhibiting the activity of PFK-2, resulting in the  activation of gluconeogenesis and inhibition of glycolysis.

7 0
2 years ago
Which is the correct symbol for an isotope of bromine with 35 protons and 38 neutrons? A) 35Br38 B) 73Br C) 35Br D) 73Br
Brilliant_brown [7]
I think it may be B.


6 0
2 years ago
Read 2 more answers
Please do all of this I will give you 29 points thats all I have. I will mark brainliest if I figure out how too.
Romashka [77]

Answer:

1.  chemical property

2.  chemical property

3.  chemical change

4.  physical change

5.  physical property

6.  chemical change

7.  chemical change

8.  chemical property

9.  physical property

10.  physical property

11.  physical change

12.  chemical change

13.  chemical change

14.  chemical change

15.  true

16.  true

17.  false

18.  true

19.  false

20.  true

21.  chemical change

22.  physical change

23.  chemical change

24.  chemical change

Explanation:

Like it says in the worksheet, for questions 1-14, you can tell the difference between a property and change by whether there is a verb in the description.

If the object is simply changing form (melting, freezing), it is a physical change or property.  The object can be returned to the state it was in originally without much difficulty.  You can freeze water and turn it into ice.  You can just as easily melt the ice and turn it into water again.

If the object is actually changing its composition or a reaction is taking place (baking bread, combustion), it is a chemical change or property.  It is not as easy and sometimes even impossible to change back to its original state.  If you have a bike that is rusted, you cannot really do much to change it back to how it was before it got rusty.

Hope this helps! <3

8 0
2 years ago
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