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TiliK225 [7]
3 years ago
11

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction? carbon + oxygen

+ carbon dioxide carbon + oxygen → carbon dioxide carbon dioxide → carbon + oxygen carbon dioxide + carbon → oxygen NextReset
Chemistry
2 answers:
zmey [24]3 years ago
8 0

Answer: CO2

Explanation:

frutty [35]3 years ago
6 0
C (solid) + O2 (gas) -> C02 (gas)

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What type of compound is calcium oxide
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What is the indicator of the number of ions in solution?
Andru [333]

Answer:

The amount of solute added.

Explanation:

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One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K
mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (s_{2} - s_{1}), in joules per gram-Kelvin, by the following model:

s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}} (1)

Where:

m - Mass, in kilograms.

c_{w} - Specific heat of water, in joules per kilogram-Kelvin.

T_{1}, T_{2} - Initial and final temperatures of water, in Kelvin.

If we know that m = 1\,kg, c_{w} = 4190\,\frac{J}{kg\cdot K}, T_{1} = 373.15\,K and T_{2} = 288.15\,K, then the change in entropy for the entire process is:

s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}

s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0
3 years ago
How does the periodic table help in predicting the formula of a stable ionic compound?
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A. This is a FALSE statement because Metals in Group 1 form cations with a +1 charge and not -1. 

B. This is a TRUE statement. 

C. This is a FALSE statement because metals do not form anions i.e. negatively charged ions but form cations i.e. positively charged ions. 

D. This is a FALSE statement because metals do not form anions i.e. negatively charged ions but form cations i.e. positively charged ions. 
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