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Butoxors [25]
3 years ago
9

How many moles of calcium chloride are needed to react completely with 6.2 moles of silver nitrate

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
8 0

Answer:

3.1 mol

Step-by-step explanation:

The balanced equation is

CaCl₂ + 2AgNO₃ ⟶ Ca(NO₃)₂ + 2AgCl

You want to convert moles of AgNO₃ to moles of CaCl₂.

The molar ratio is 2 mol AgNO₃:1 mol CaCl₂

Moles of CaCl₂ = 6.2 mol AgNO₃ × (1 mol CaCl₂/2 mol AgNO₃)

Moles of CaCl₂ = 3.1 mol CaCl₂

The reaction will require 3.1 mol of CaCl₂.

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Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet
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The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

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So,  dSsurr = - (-114 × 1000) / 355

dSsurr = +321.12 J/K

Hence, the value of dSsurr is +321.12 J/K

For a reaction to be spontaneous, dG<0,

Also dStotal = dSsys + dSsurr > 0

It is known that dG = dHsys - TdSsys,

Now let us assume,

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355 × dSsys > -114 × 1000

dSsys > -321

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dSsys + dSsurr > 0

dStotal > 0

Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.



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