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Natalka [10]
3 years ago
14

Who can help me with a few chemistry balancing equtions?

Chemistry
1 answer:
hoa [83]3 years ago
6 0
<span>Who can help me with a few chemistry balancing equations? 
Me. Just show me the equations :)</span>
You might be interested in
18. The mass of a quantity of NiCl2 is 24.6 g. How many formula units are in the sample?
Charra [1.4K]

Answer is: A. 1.1 3 1023 NiCl2 formula units.

m(NiCl₂) = 24.6 g; mass of nickel(II) chloride.

M(NiCl₂) = 129.6 g/mol; molar mass of nickel(II) chloride.

n(NiCl₂) = m(NiCl₂) ÷ M(NiCl₂).

n(NiCl₂) = 24.6 g ÷ 129.6 g/mol.

n(NiCl₂) = 0.19 mol; amount of nickel(II) chloride.

Na = 6.022·10²³ 1/mol; Avogadro constant.

N(NiCl₂) = n(NiCl₂) · Na.

N(NiCl₂) = 0.19 mol · 6.022·10²³ 1/mol.

N(NiCl₂) = 1.13·10²³; number of formula units.

4 0
4 years ago
Read 2 more answers
Consider the following reaction where Kc = 6.50×10-3 at 298 K: 2NOBr(g) 2NO(g) + Br2(g) A reaction mixture was found to contain
Aleks [24]

Answer:

This reaction isn't yet at an equilibrium. It must shift in the direction of the reactant (namely \rm NOBr\; (g)) in order to reach an equilibrium.

For this mixture, the reaction quotient is Q_c = 0.0126.

Explanation:

A reversible reaction is at equilibrium if and only if its reaction quotient Q_c is equal to the equilibrium constant K_c.

Start by calculating the equilibrium quotient Q_c of this reaction. Given the reaction:

\rm 2\; NOBr\; (g) \rightleftharpoons 2\; NO\; (g) + Br_2\; (g).

Let [\mathrm{NOBr\; (g)}], [\mathrm{NO\; (g)}], and [\mathrm{Br_2\; (g)}] denote the concentration of the three species. The formula for the reaction quotient of this system will be:

\displaystyle Q_c = \frac{[\mathrm{NO\; (g)}]^2 \cdot [\mathrm{Br_2\; (g)}]}{[\mathrm{NOBr\; (g)}]^2}.

(Note, that in this formula, both [\mathrm{NO\; (g)}] and [\mathrm{NOBr\; (g)}] are raised to a power of two. That corresponds to the coefficients in the balanced reaction.)

Calculate the reaction quotient given the concentration of each species:

\displaystyle Q_c = \frac{[\mathrm{NO\; (g)}]^2 \cdot [\mathrm{Br_2\; (g)}]}{[\mathrm{NOBr\; (g)}]^2} \approx 1.26\times 10^{-2} = 0.0126.

(Note that the unit is ignored.)

Apparently, Q_c > K_c. Since Q_c and K_c are not equal, this reaction is not at an equilibrium. If external factors like temperature stays the same,

Keep in mind that Q_c denotes a quotient. To reduce the value of a quotient, one may:

  • reduce the value of the numerator,
  • increase the value of the denominator, or
  • both.

In Q_c, that means reducing the concentration of the products while increasing the concentration of the reactants. In other words, the system needs to shift in the direction of the reactants before it could reach an equilibrium.

8 0
3 years ago
A decrease in temperature will affect the rate of which of the following reaction
jok3333 [9.3K]
You didn't put the reactions
6 0
3 years ago
What is the molarity of the solution with a volume of 23.47 Liters and 14.968 moles?
MrMuchimi

Answer:

0.6378 M

Explanation:

Molarity is defined by Moles per liter.

Plugging the given information in, we get (14.968 moles)/(23.47 L) which comes out to be about 0.6378 M

3 0
3 years ago
2. Which types of changes observe the law of
mart [117]
D) physical and chemical changes
3 0
3 years ago
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