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vredina [299]
3 years ago
10

You have 250.0 mL of 4.00 M sugar solution. You added 216.1 mL of water to this solution. Determine the concentration of the sug

ar solution after the addition of water.
Chemistry
1 answer:
ozzi3 years ago
7 0

Answer:

M_2=2.15M

Explanation:

Hello!

In this case, since the dilution processes are characterized by the addition of extra solvent, in this case water, to an initial solution in order to decrease the concentration of the solute, in this case sugar; as water is added, the moles of sugar remain unchanged, so the following equation can be written:

n_1=n_2\\\\M_1V_1=M_2V_2

Whereas 1 accounts for the initial 250.0 mL of 4.00 M sugar and 2 for the concentration at the new volume which is:

V_2=250.0mL+216.1mL=466.1mL

Thus, the final concentration is:

M_2=\frac{M_1V_1}{V_2} =\frac{250.0mL*4.00M}{466.1mL} \\\\M_2=2.15M

Best regards!

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