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3 years ago

What is the molarity of the solution with a volume of 23.47 Liters and 14.968 moles?

Chemistry

1 answer:

MrMuchimi3 years ago

3 0

Answer:

0.6378 M

Explanation:

Molarity is defined by Moles per liter.

Plugging the given information in, we get (14.968 moles)/(23.47 L) which comes out to be about 0.6378 M

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I believe the correct answer is B

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4 years ago

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Answer:

https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186

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3 years ago

Not sure how to do this

faust18 [17]

Answer:

0.0991 M

Explanation:

Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.

H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O

Step 2: Calculate the moles of oxalic acid

The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:

$0.153g \times \frac{1mol}{90.03g} = 1.70 \times 10^{-3} mol$

Step 3: Calculate the moles of sodium hydroxide

The molar ratio of H₂C₂O₄ to NaOH is 1:2.

$1.70 \times 10^{-3} molH_2C_2O_4 \times \frac{2molNaOH}{1molH_2C_2O_4} = 3.40 \times 10^{-3} molNaOH$

Step 4: Calculate the molarity of sodium hydroxide

$\frac{3.40 \times 10^{-3} mol}{34.3 \times 10^{-3} L} = 0.0991 M$

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4 years ago

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Answer:

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Explanation:

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Hope this helped!

Have a supercalifragilisticexpialidocious day!

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3 years ago