Answer:
P = 28.5 atm
Explanation:
PV = nRT => P = nRT/V
P = Pressure = ?
n = moles of sample = mass/molar mass = 26g/44g·mol⁻¹ = 0.619 mole CO₂
R = gas constant = 0.08206 L·atm/mol·K
T = temperature in Kelvin = (35 + 273)K = 308K
V = volume in Liters = 550 ml = 0.550 L
Pressure (P) = nRT/V
= (0.619 mole)(0.08206 L·atm/mol·K)(308K)/(0.550 L) = 28.5 atm
The electron configuration that corresponds to the valence electrons of an element for which there is an especially large jump between the second and third ionization energies is ns^2.
The valence electron configuration of an atom refers to the arrangement of electrons on the outermost shell of the atom.
Recall that a large jump in ionization energy occurs when electrons are removed from inner shells of the atom.
If we study our options closely, we will discover that option A has only two electrons in the valence shell (ns^2).
This means that the third ionization energy involves removing electrons from an inner shell which leads to large jump.
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Hydrogen Ions exist in acid solutions.
Answer:
13,200 mL
Explanation:
multiply by 1000 to go from L to mL
Answer:
Therefore 500 ml of solution have 0.25 mol of NaCl .. = 14.61 g (ans.)
Explanation:
