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dedylja [7]
3 years ago
7

A bag contains 40 tickets, each numbered between 1-40. If a ticket is drawn at random, find the probability of it being odd or l

ess than 26
Mathematics
1 answer:
Crank3 years ago
3 0

Answer:

you have a 50% chance of getting an odd number and a 60% chance of getting a number less than 26.

Step-by-step explanation:

Between 1 and 40 there are 20 odd numbers

20÷ 40 x 100=50, This means you have a 50% (20:20) chance of getting an odd number.

Between 1 and 40 there 25 numbers less than 26

15÷25 x 100=60, This means you have a 60% (25:15) chance of getting a number under 26.

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Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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In this problem:

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The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

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0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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