Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
Proportion
3 parts milk. 12cups
2 parts sugar X
8 cups sugar
Answer:
3, in both a), b)
Step-by-step explanation:
a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.
Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is
. In particular, the value we are looking for is
.
If you would like to compute the equation of the tangent line, we can use the point-slope equation to get 
b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to
.