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Stolb23 [73]
3 years ago
14

An 8000-N car is traveling at 12 m/s along a horizontal road. When the brakes are applied, the car skids (slides) to a stop in 4

.0 s. Find the work done on the car.
Physics
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

192000 J or 192 kJ

Explanation:

Work done = Force × distance moved along the direction of force.

From the question,

W = F×d............... Equation 1

Where W = work done by the car, F = Force of the car, d = distance move by the car along the direction of the force.

We can calculate for d using the equation of motion

d = (v+u)t/2..................... Equation 2

Where v = Final velocity of the car, u = Initial velocity of the car, t = time.

Given: u = 12 m/s, v = 0 m/s(skids to a stop), t = 4.0 s

Substitute into equation 2

d = (12+0)4/2

d = 24 m.

Also given: F = 8000 N

Substitute into equation 1

W = 8000×24

W = 192000 J

W = 192 kJ.

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Jlenok [28]

Answer:

same 0.81m

Explanation:

in this problem if we assume there no resistance of any sort. and we apply the energy conservation

change in Potential energy = change in kinetic energy

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the above relation suggests that the speed at the bottom is only depending on the height it is released from not on the shape, mass or radius.

so at the bottom

put h = 0.81m

9.81 * 0.81 * 2 = v^2

v=3.99 m/s

both CYLINDER and SPHERE will have same velocity at the bottom if released from the same height irrespective of shape and size

3 0
3 years ago
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Yuri [45]
P=W/t

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W=Work
t=Time

Convert 16 minutes in seconds:
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P=6720/960=7.23 W [Watt]
3 0
3 years ago
There are many interesting applications of our energy density model to the flow of blood in the human circulatory system. One in
qaws [65]

Answer:

Pressure increases due to enlargement

Explanation:

Energy density is just a fancy name for pressure

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thus, Air pressure 1 + h1d1g = Air pressure 2 + h2d1g

= Air pressure 3 + (h2-h1)d2g +h1d1g

from the first 2, we get that since h2>h1, AP2<AP1

from the next 2, we get that since d2<d1, AP3>AP2

from first and third, we get that AP1>AP3

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for fluids flowing in tubes (blood vessel in this case)

P+0.5dv^2 + gh is constant (also called the bernoulli equation

for the same blood vessel, the heights remain same i.e h1=h2

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Troposphere is the answer
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The distance and displacement of a object in motion can be the same (true or false)
Rasek [7]

Aswer:

False, the values ​​of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.

Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.

<u>xXCherryCakeXx</u>.

4 0
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