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Stolb23 [73]
4 years ago
14

An 8000-N car is traveling at 12 m/s along a horizontal road. When the brakes are applied, the car skids (slides) to a stop in 4

.0 s. Find the work done on the car.
Physics
1 answer:
kicyunya [14]4 years ago
5 0

Answer:

192000 J or 192 kJ

Explanation:

Work done = Force × distance moved along the direction of force.

From the question,

W = F×d............... Equation 1

Where W = work done by the car, F = Force of the car, d = distance move by the car along the direction of the force.

We can calculate for d using the equation of motion

d = (v+u)t/2..................... Equation 2

Where v = Final velocity of the car, u = Initial velocity of the car, t = time.

Given: u = 12 m/s, v = 0 m/s(skids to a stop), t = 4.0 s

Substitute into equation 2

d = (12+0)4/2

d = 24 m.

Also given: F = 8000 N

Substitute into equation 1

W = 8000×24

W = 192000 J

W = 192 kJ.

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Let the rise in temperature be 5^0C

The expansion in length due to change in temperature is given by the expression lαΔt , where l is the length, α is the  coefficient of linear expansion, Δt is the change in temperature.

Here l = 93 m, α = 1.7*10^{-5}  ^0C^{-1}, and Δt = 5^0C

So expansion in length = 93*1.7*10^{-5}*5 = 0.007905 m = 0.79*10^{-3}m

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3 years ago
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leonid [27]

I believe it is the block of lead

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3 years ago
Hanging from a horizontal beam are nine simple pendulums of the following lengths:
LenaWriter [7]

Answer:

Options d and e

Explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

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when ω= 2rad/sec

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L=\frac{9.8}{4^{2} }

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

8 0
4 years ago
What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?
sveta [45]
Momentum = (mv). 
<span>(2110 x 24) = 50,640kg/m/sec. truck momentum. </span>
<span>Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec</span>
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Which of the following could you measure with a thermometer
irinina [24]
[:] Answer [:]

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3 years ago
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